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elixir [45]
3 years ago
12

The triangles below are similar because of the:

Mathematics
1 answer:
STALIN [3.7K]3 years ago
8 0

Answer:

ΔABC and  ΔXYZ are SIMILAR by SSS property of similarity.

Step-by-step explanation:

SSS Similarity Theorem:

Two triangles are said to be similar if their  CORRESPONDING SIDES are proportional.

In ΔABC and  ΔXYZ, if \frac{AB}{XY}  = \frac{BC}{YZ} = \frac{AC}{XZ}  , then  △ABC∼△YZX

Here, in ΔABC and  ΔXYZ

AB = 9, BC = x , AC = 12

Similarly, XY = 3, YZ = 2, ZX = 4

Here,

\frac{AB}{XY} = \frac{9}{3}  = 3\\\frac{BC}{YZ} = \frac{x}{2} \\\frac{Ac}{Xz} = \frac{12}{4}  = 3

⇒ Corresponding sides are in the ratio of 3, if BC  =6 units

Hence, if BC  = 6 units, then the ΔABC and  ΔXYZ are SIMILAR by SSS property of similarity.

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A survey of Massachusetts high school students showed that the mean number of hours these students reported watching crime TV sh
masha68 [24]

Answer:

a) Z = -0.5

b) Z = 1.5

c) 93.32% of students watch less than 3.6 hours of shows a week

d) 62.57% of the sample watches between 2 hours and 3.6 hours of crime shows a week

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 2.4, \sigma = 0.8

a. Find the z-score for a student who reported watching 2 hours of crime shows a week.

This is Z when X = 2. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2 - 2.4}{0.8}

Z = -0.5

b. Find the z-score for a student who reported watching 3.6 hours of crime shows a week

X = 3.6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.6 - 2.4}{0.8}

Z = 1.5

c. What percentage of students watch less than 3.6 hours of shows a week?

pvalue of Z when X = 3.6.

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.6 - 2.4}{0.8}

Z = 1.5

Z = 1.5 has a pvalue of 0.9332

93.32% of students watch less than 3.6 hours of shows a week

d. What percentage of the sample watches between 2 hours and 3.6 hours of crime shows a week?

pvalue of Z when X = 3.6 subtracted by the pvalue of Z when X = 2.

X = 3.6

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.6 - 2.4}{0.8}

Z = 1.5

Z = 1.5 has a pvalue of 0.9332

X = 2

Z = \frac{X - \mu}{\sigma}

Z = \frac{2 - 2.4}{0.8}

Z = -0.5

Z = -0.5 has a pvalue of 0.3075

0.9332 - 0.3075 = 0.6257

62.57% of the sample watches between 2 hours and 3.6 hours of crime shows a week

7 0
3 years ago
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