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Rasek [7]
3 years ago
6

Sec^2 theta/tan theta = sec theta x csc theta

Mathematics
1 answer:
Andreas93 [3]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

• tan x = \frac{sinx}{cosx}

• sec x = \frac{1}{cosx}, csc x = \frac{1}{sinx}

Consider the left side with x = Θ

\frac{sec^2x}{tanx}

=\frac{1/cos^2x}{\frac{sinx}{cosx} }

= \frac{1}{cos^2x} × \frac{cosx}{sinx}

= \frac{1}{cosxsinx}

= \frac{1}{cosx} × \frac{1}{sinx}

= secxcscx = right side ⇒ verified


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