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IrinaVladis [17]
3 years ago
7

I NEED THE CORRECT ANSWER IN ORDER TO PASS PLS HELP! I DO NOT HAVE A LOT OF TIME

Mathematics
1 answer:
elena55 [62]3 years ago
6 0

Answer:

1. 3x - 4 > 17

2. 3x - 4 < 17

3. 3x - 4 ≤ 17

4. 3x - 4 < 17

5. 3x - 4 ≥ 17

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Could you please solve this? I do not understand it.
oksano4ka [1.4K]
#2
Change mixed numbers to improper fractions. Then change division to multiplication by the reciprocal.
1 1/2 divided by 3/5=
(3/2) * (5/3) = 5/2 = 2 1/2
#3
(5/9) divided by (5/3)
(5/9) * (3/5) =3/9 = 1/3
3 0
4 years ago
Figure out what n equals in this equation:<br> 6n + 4 = -26
aniked [119]

Answer:

n=-5

Step-by-step explanation:

6n+4=-26

=>6n=-26-4

=>6n=-30

=>n= -30/6

=>n=-5

7 0
3 years ago
Read 2 more answers
An open square box of volume 514,500 cubic inches has a square base and five partitions inside that are parallel to two sides. F
Aleksandr [31]

The solution is in the attachment

5 0
3 years ago
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Belle walks n mile each morning and 16 miles each evening.
Rom4ik [11]

This makes no since.

6 0
3 years ago
Analyze the diagram below and answer the question that follows
laiz [17]

Answer:

C. 40.2°

Step-by-step explanation:

Cosine rule (real handy to remember): c² = a² + b² - 2·a·b·cos(γ)

If you don't know this yet, look it up but in short: c, a and b are the lengths of the sides of the triangle, the angle opposite side a is called α, for b it is β and for c it is γ. That's the convention I've always used anyway, you can call them whatever of course. Anyhow:

c² = a² + b² - 2·a·b·cos(γ)

⇒ |AC|² = |AB|²+|BC|²-2·|AB|·|BC|·cos(∠B)

⇒ |AC|²-|AB|²-|BC|² = -2·|AB|·|BC|·cos(∠B)

⇒ ( |AC|²-|AB|²-|BC|² ) / ( -2·|AB|·|BC| ) = cos(∠B)

⇒ ∠B = arccos( ( |AC|²-|AB|²-|BC|² ) / ( -2·|AB|·|BC| ) )

         = arccos( ( 11²-16²-16² ) / ( -2·16·16 ) )

         = 40.21101958°

         ≈ 40.2°

6 0
2 years ago
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