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butalik [34]
2 years ago
12

10 Points<>I need help ASAP!!!

Mathematics
1 answer:
ZanzabumX [31]2 years ago
8 0

Answer:

Step-by-step explanation:

A and D

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Choose the correct zeros for the following quadratic function.
sesenic [268]

Answer:

c

Step-by-step explanation:

x^2+5x-14

factor by finding multiples of (-14) that add up to 5

7*-2=-14

7+-2=5

So the factored out equation is (x+7)(x-2)

Therefore the solutions are x=-7 and x=2

6 0
3 years ago
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Jack is sharing 3 bananas with 3 Friends. Which expression represents the amount each one will get if they share them equally?
Afina-wow [57]
They will each get 1 banana can i get brainiest please i was first and i barley have any
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2 years ago
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(05.05) Which of the following inequalities matches the graph? (1 point)​
alexira [117]

Answer:  Choice A.   x \le -7

=====================================================

Explanation:

Every point in the shaded region has an x coordinate that is equal to -7 or smaller.

Example points include

  • (-8, 0)
  • (-10, 2)
  • (-9, -5)

The y coordinate does not matter. All that matters is the x coordinate. The boundary line is the equation x = -7, representing all points that have x coordinate of -7. The solid boundary line says to the reader "any point on this boundary line is part of the shaded region solution set". This inclusion is due to the "or equal to" of the inequality sign.

6 0
2 years ago
A bag contains 4 red balls, 2 green balls, 3 yellow balls, and 5 blue balls. Find each probability for randomly removing balls w
AfilCa [17]

Answer:

\frac{15}{4802}, \frac{15}{9604}, \frac{9}{2401}, \frac{9}{4802}

Step-by-step explanation:

The bag has a total of (4+2+3+5) = 14 balls. Set up the proportions:

Red: \frac{4}{14}

green: \frac{2}{14}

yellow: \frac{3}{14}

blue: \frac{5}{14}

Now solve!

Removing 1 yellow, 1 red, 1 green, and 1 blue = \frac{3}{14} \cdot \frac{4}{14}  \cdot \frac{2}{14}  \cdot \frac{5}{14} =\frac{15}{4802}

Removing 1 blue, 1 green, 1 green, and 1 yellow = \frac{5}{14} \cdot \frac{2}{14}  \cdot \frac{2}{14}  \cdot \frac{3}{14} =\frac{15}{9604}

Removing 1 red, 1 red, 1 yellow, and 1 yellow = \frac{4}{14} \cdot \frac{4}{14}  \cdot \frac{3}{14}  \cdot \frac{3}{14} =\frac{9}{2401}

Removing 1 green, 1 yellow, 1 yellow, and 1 red = \frac{2}{14} \cdot \frac{3}{14}  \cdot \frac{3}{14}  \cdot \frac{4}{14} =\frac{9}{4802}

4 0
2 years ago
You roll two fair dice, a green one and a red one.
olga_2 [115]

Answer:

(a) yes

(b) 1/36

(c) 1/36

(d) 1/18

Step-by-step explanation:

(a) yes they are independent as the outcome of one does not affect the outcome of the other.

(b) As the dice are fair, each possible number (1 through 6) has the same probability of being rolled.

P(1 on green die) = 1/6

P(2 on red die) = 1/6

Therefore, P(1 on green die) AND P(2 on red die) = 1/6 × 1/6 = 1/36

(c) Again, as the dice are fair, each possible number (1 through 6) has the same probability of being rolled.

P(2 on green die) = 1/6

P(1 on red die) = 1/6

Therefore, P(2 on green die) AND P(1 on red die) = 1/6 × 1/6 = 1/36

(d) p[(1 on green die and 2 on red die) OR (2 on green die and 1 on red die)

= 1/36 + 1/36

= 2/36

= 1/18

3 0
2 years ago
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