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igomit [66]
3 years ago
13

Fencing costs $6 a foot. What would the least expensive fence for an area of 48 square feet cost? What would the most expensive

fence for the same area cost? Each width and length must be a whole number.
Mathematics
1 answer:
Brums [2.3K]3 years ago
8 0
The most expensive would be one foot wide and forty eight feet long (or vice versa) and the least expensive would be eight foot wide and six foot long (or vice versa).
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Mary earned $97.50 in 6.5 hours.If Mary works for 8 hours, how much can she expect to earn?
laila [671]
We first work out how much Mary will earn in one hour by doing 97.50/6.5 = 15
We then multiply this answer by 8 to work out how much she is expected to earn in 8hours
15*8= 120
So Mary will earn $120 in 8 hours
3 0
2 years ago
For Valentine's Day, Shawn baked 240 cookies for his entire family. If he baked half of the cookies on Monday, a third of the re
s344n2d4d5 [400]

Answer: 80 cookies

Step-by-step explanation: He had to bake 240 cookies and on Monday he baked have of them which is 120 cookies. Then on Tuesday he baked a third of the remaining so if the baked 120 and has to bake 240 he still has to bake 120 now 1/3 * 120 = 40 so he baked 40 cookies on Tuesday on Wednesday he still has to bake the reaming cookies so 120 + 40 = 160 and 240 - 160 = 80 so on Wednesday he has to bake 80 cookies.

8 0
3 years ago
In ΔXYZ, ∠X=82° and ∠Y=84°. ∠XWZ=90° and XY=97. Find the length of XW to the nearest integer.
ivanzaharov [21]

Check the picture below to the left, let's use those sides with the law of sines

\textit{Law of sines} \\\\ \cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{sin(14^o)}{97}=\cfrac{sin(84^o)}{XZ}\implies XZ = \cfrac{97\cdot sin(84^o)}{sin(14^o)}\implies XZ \approx 398.76 \\\\\\ \stackrel{\textit{now using SOH CAH TOA}}{cos(82^o) = \cfrac{XW}{XZ}}\implies XZcos(82^o)=XW \\\\\\ 398.76cos(82^o)\approx XW\implies 55.497\approx XW\implies \stackrel{\textit{rounded up}}{55=XW}

7 0
2 years ago
Solving Rational equations. LCD method. Show work. Image attached.
Dmitry [639]

Answer:

b=1

Step-by-step explanation:

The given rational equation is

\frac{2b-5}{b-2} -2=\frac{3}{b+2}

The Least Common Denominator is (b+2)(b-2).

Multiply each term in the equation by the LCD.

(b+2)(b-2)\times \frac{2b-5}{b-2} -(b+2)(b-2)\times2=(b+2)(b-2)\times\frac{3}{b+2}

Simplify;

(b+2)\times \frac{2b-5}{1} -2(b+2)(b-2)=(b-2)\times\frac{3}{1}

(b+2)(2b-5) -2(b+2)(b-2)=3(b-2)

Expand and group similar terms

2b^2-5b+4b-10 -2(b^2-4)=3b-6

2b^2-5b+4b-10 -2b^2+8=3b-6

-b-2=3b-6

3b+b=-2+6

4b=4

b=1

3 0
2 years ago
The function f (t) = 12(1 +0.03) can be used to determine the population, in thousands of a town t years
Alja [10]

f= the original amount of people, a steady growth throughout the years

t=time

In 1955 the population was 12 thousand. Compared to the current population of 12.36 thousand, the population then was roughly 77%.

5 0
2 years ago
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