Let the three consecutive integers be x , x+1 ,x+2
Given, sum of three consecutive integers = -126
x +x+1+ x+2 = -126
3x +3 = -126
3x = -126 -3
3x = -129
x = -129/3
x = - 43
x +1 = -42
x +2 = -41
Answer:
x=2
Step-by-step explanation:
Hope it helps you!
Answer:
all real numbers
Step-by-step explanation:
you can create any value for y with a value for x, hence the range is "everything".
I hope this helps you
m (ACD)=m (ABD)
4x+4=6x-14
2x=18
x=9
m (ACD)=4x+4 =4.9+4=40
Answer:
Either x≈ -1.12 or x ≈0.45
Step-by-step explanation:
Using the quadratic formula to solve this, we will follow the steps below;
First, write down the quadratic formula;
x = -b ±√b² - 4ac /2a
From the question, the equation given is: 6x²+4x−3=0
comparing the equation given withe standard equation ax² + bx + c=0
a= 6 b= 4 and c = -3
We can now proceed to insert the values into the formula;
x = -4 ±√4² - 4(6)(-3) /2(6)
x = -4 ±√16+72 /12
x = -4 ±√88 /12
Either x = -4+√88 /12
x ≈0.45
OR
x = -4 -√88 /12
x≈ -1.12
Either x≈ -1.12 or x ≈0.45
