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AysviL [449]
3 years ago
15

A gardener has 27 pansies and 36 daises. He plants and an equal number of each type of flower in each row. What is the greatest

possible number of pansies in each row? (GCF)
Mathematics
1 answer:
Daniel [21]3 years ago
8 0

Answer:

The answer to your question is 9 pansies per row.

Step-by-step explanation:

Data

Pansies = 27

Daisies = 36

Process

1.- Find the GCF

                                  27   36   2

                                  27   18    2

                                  27     9   3

                                    9     3   3

                                    3      1   3

                                     1

2.- Conclusion

The GCF is the product of the prime numbers that divide both numbers at the same time.

In this example, the GCF is 3x 3 = 9

Then, the greatest number of Pansies is 9

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Find the maximum and minimum values of the function f(x,y)=2x2+3y2−4x−5 on the domain x2+y2≤100. The maximum value of f(x,y) is:
ryzh [129]

First find the critical points of <em>f</em> :

f(x,y)=2x^2+3y^2-4x-5=2(x-1)^2+3y^2-7

\dfrac{\partial f}{\partial x}=2(x-1)=0\implies x=1

\dfrac{\partial f}{\partial y}=6y=0\implies y=0

so the point (1, 0) is the only critical point, at which we have

f(1,0)=-7

Next check for critical points along the boundary, which can be found by converting to polar coordinates:

f(x,y)=f(10\cos t,10\sin t)=g(t)=295-40\cos t-100\cos^2t

Find the critical points of <em>g</em> :

\dfrac{\mathrm dg}{\mathrm dt}=40\sin t+200\sin t\cos t=40\sin t(1+5\cos t)=0

\implies\sin t=0\text{ OR }1+5\cos t=0

\implies t=n\pi\text{ OR }t=\cos^{-1}\left(-\dfrac15\right)+2n\pi\text{ OR }t=-\cos^{-1}\left(-\dfrac15\right)+2n\pi

where <em>n</em> is any integer. We get 4 critical points in the interval [0, 2π) at

t=0\implies f(10,0)=155

t=\cos^{-1}\left(-\dfrac15\right)\implies f(-2,4\sqrt6)=299

t=\pi\implies f(-10,0)=235

t=2\pi-\cos^{-1}\left(-\dfrac15\right)\implies f(-2,-4\sqrt6)=299

So <em>f</em> has a minimum of -7 and a maximum of 299.

4 0
3 years ago
A company is designing a new cylindrical water bottle. The volume of the bottle will be 211 cm^3. The height of the water bottle
Zinaida [17]

Answer:

The correct answer is 2.912 cm.

Step-by-step explanation:

A company is designing a new cylindrical water bottle.

Volume of a cylinder is given by π × r^{2} × h, where h is the height of the cylinder and r is the radius of the cylinder.

The volume of each bottle will be 211 cm^{3}.

The height (h) of the water bottle be 7.9 cm.

Let the radius of the bottle be r cm.

∴ π × r^{2} × h = 211 ; (π = 3.15)

⇒ r^{2} × 24.885 = 211

⇒ r = 2.912

The radius of the water bottle is 2.912 cm.

4 0
3 years ago
If f(×)=1/3×^2+5find f(-9)
Snezhnost [94]

Answer:

I think this is the answer

f( - 9) =  \frac{1}{3( - 9) {}^{2} }  + 5 \\  =  \frac{1216}{243}  \\  = 5.0041

5 0
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In a certain sequence of numbers, each term after the first is found by doubling and then adding $3$ to the previous term. If th
eimsori [14]
Given a_7=125 you can find a_6:

a_6= \frac{125-3}{2} =61
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3 years ago
Jake gave the cashier $50 to pay for 5 pairs of jeans. The cashier gave him
levacccp [35]

Answer:

8.85

Step-by-step explanation:

7 0
3 years ago
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