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3 years ago

Is this answer 6?......

Mathematics

2 answers:

Sergeu [11.5K]3 years ago

6 0

Answer: I believe so, putting it in a statement of ____ = _____ should require the statement to be true if you need more help just ask away

Step-by-step explanation:

gayaneshka [121]3 years ago

5 0

Answer:

no, the answer is 10 because they are supplementary lines which equal to 180. So basically 10 takes the place of X when your doing the equation. (shown below) vvvv

Step-by-step explanation:

DE= 8x + 20

EC= 3x + 50

DE= 8(10) +20=100

EC= 3(10) + 50=80

100+80=180

X=10

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Find the measure of x.

Ratling [72]

<h3>Answer: B. x = 6</h3>

==========================================================

Explanation:

Since the vertical lines are parallel, this means the alternate exterior angles shown are congruent.

Set them equal to each other and solve for x.

15(x+2) = 120

15x+30 = 120

15x = 120-30

15x = 90

x = 90/15

x = 6

Or we could have the steps like this

15(x+2) = 120

x+2 = 120/15

x+2 = 8

x = 8-2

x = 6

7 0

2 years ago

At 6 a.m., the temperature was –12°C. By 9 a.m., the temperature had risen by 8°C. By noon, the temperature was double what the

Volgvan

First, you must use ADDITION to find -12 + 8 (-4)
Then, use MULTIPLICATION to find -4*2 (16

1) Addition
2) Multiplication

8 0

3 years ago

Read 2 more answers

A bag contains 3 red marbles 4 blue marbles and 7 Green marbles if two marbles are drawn out of the bag what is the probability

mr_godi [17]

Answer:

0.368

Step-by-step explanation:

Number of red marbles= 3

Number of blue marbles= 4

Number of green marbles= 7

Total number of marbles= 3+4+7= 14

Let the first ball is taken out to be red

P(R)= $\frac{3}{14}$

than again a second ball is drawn, number of balls left= 14-1=13

Number of red= 2

P(R)= $\frac{2}{13}$

Total probability= $\frac{3}{14}$ + $\frac{2}{13}$

Total probability= 0.368

Hence, the correct answer is 0.368

3 0

3 years ago

Use long division to divide x^3+x^2-2x+14 by x+3

bekas [8.4K]

First, $x^3=x^2\cdot x$ , and if we multiply $x+3$ by $x^2$ we get

$x^3+3x^2$

Subtracting this from the numerator gives a remainder of

$-2x^2-2x+14$

Next, $-2x^2=-2x\cdot x$ , and if we multiply $x+3$ by $-2x$ we have

$-2x^2-6x$

and subtracting this from the previous remainder, we end up with a new remainder of

$4x+14$

Next, $4x=4\cdot x$ , and if we multiply $x+3$ by $4$ we get

$4x+12$

Subtracting from the previous remainder, we get a new remainder of

$2$

which contains no more factors of $x$ , so we're done.

So,

$\dfrac{x^3+x^2-2x+14}{x+3}=x^2-2x+4+\dfrac2{x+3}$

8 0

3 years ago

3x + 2x + 4 + 5x - 8

yawa3891 [41]

Answer:

the answer is 10 x − 4

5 0

2 years ago