<u><em>I am doing this problem assuming that you mean to solve for m and n as x and y do not exist in this system of equations.</em></u>
<u><em /></u>
-4m+2n=6
-4m+n=8
We can see that the coefficient of x for both equations are -4; therefore, elimination with subtraction is possible.
<u>First equation - second equation</u>
n=-2
<u>Then substitude back in to solve for m</u>
-4m+(-2)=8
4m=10
m=5/2
Therefore the answer is
n= - 2
m= 5/2
I hope this helped and if you have any questions please ask.
The complete question in the attached figure
we know that
<span>applying the Pythagorean theorem in triangle ABC
</span>AC²=AB²+BC²----------> AB²=AC²-BC²---------> 10²-8²-------> AB²=36-----> AB=6
in the triangle ABC
tan a=BC/AB--------> 8/6--------> tan a=4/3
tan c=AB/BC--------> 6/8--------> tan c=3/4
in the triangle ABD
tan a=BD/AD---------> tan a=BD/x-------> BD=x*tan a
BD=x*(4/3)-----------> equation 1
in the triangle BDC
tan c=BD/DC------------------> BD=(10-x)*tan c------> BD=(10-x)*(3/4)
BD=(10-x)*(3/4)-------------> equation 2
equal 1 and 2
x*(4/3)=(10-x)*(3/4)------> 16x=9*(10-x)--------> 16x=90-9x----> 25x=90
x=90/25-----------> x=3.6
BD=x*(4/3)--------> BD=3.6*(4/3)----------> BD=4.8 units
the answer is BD=4.8 units
C . Two acute and two obtuse angeld
Answer:
I think the answer is 40. it will take about 20 months to have 100 dollars