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3 years ago

FAST PLEASE !!!!

Mathematics

1 answer:

zhannawk [14.2K]3 years ago

5 0

Answer:

2/3

Step-by-step explanation:

To get the slope, you do (y2-y1)/(x2-x1).

You can also remember it as rise/run, as it is the change in y/change in x.

You can make either coordinate 1 or 2, just keep it consistent with the rest of the problem.

For this, I chose (-5, -7) to be 2, and (4, -1) to be 1.

Following the formula for slope, (y2-y1)/(x2-x1), you put the values in: (-7-{-1})/(-5-4).

-7 minus -1 is -6 and -5 minus 4 is -9.

Thus you get -6/-9. Don’t forget to simplify! A negaive divided by a negative is positive, and both 6 and 9 can be divided by 3. 3 goes into 6 TWO times and into 9 THREE times.

So, you get a positive fraction, 2/3.

Hope this helped.

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Write any 4 laws of exponents.<br>

emmainna [20.7K]

$\rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}$

<em>Write any 4 laws, or properties, of exponents.</em>

<em />

<em> </em> $\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}$

$\Large\text{Law number 1:-}$

$\Large\text{$a^n*a^m=a^{n+m}$}$

$\Large\text{It states that:-}$

When we multiply together numbers with the same base,

we add the exponents.

$\Large\text{Law number 2:-}$

$\Large\text{$a^m:a^n=a^{m-n}$}$

$\Large\text{It states that:-}$

When we divide numbers with the same base, we

subtract the exponents.

$\Large\text{Law number 3:-}$

$\Large\text{$(\displaystyle\frac{x}{y}) ^n=\frac{x^n}{y^n}$}$

$\Large\text{It states that:-}$

If we have a fraction to a power, we raise the numerator and

the denominator to that power.

And then last but not least,

$\Large\textit{Law number 4:-}$

$\Large\text{$a^{-m} =\displaystyle\frac{1}{a^m}$}$

$\Large\text{It states that:-}$

If we have a number with a negative exponent, we flip it over.

<h3>Good luck with your studies.</h3>

#TogetherWeGoFar

$\rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}$

6 0

3 years ago

Read 2 more answers

What is the equation of the line that passes through the point (-1,7) and is parallel to the line y= -2x-1

Nuetrik [128]

if we look at the equation y = -2x - 1, is already in slope-intercept form, therefore, $\bf y=\stackrel{slope}{-2}x-1$ has a slope of -2.

now, parallel lines have exactly equal slopes, therefore a parallel to that one above, will have also a slope of -2, so we're really looking for a line whose slope is -2 and runs through -1, 7.

$\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{7})\qquad \qquad \qquad slope = m\implies -2\\\\\\\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-7=-2[x-(-1)]\\\\\\y-7=-2(x+1)\implies y-7=-2x-2\implies y=-2x+5$