To get the solution, we are looking for, we need to point out what we know.
1. We assume, that the number 45.5 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 45.5 is 100%, so we can write it down as 45.5=100%.
4. We know, that x is 6.81% of the output value, so we can write it down as x=6.81%.
5. Now we have two simple equations:
1) 45.5=100%
2) x=6.81%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
45.5/x=100%/6.81%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 6.81% of 45.5
45.5/x=100/6.81
(45.5/x)*x=(100/6.81)*x - we multiply both sides of the equation by x
45.5=14.684287812041*x - we divide both sides of the equation by (14.684287812041) to get x
45.5/14.684287812041=x
3.09855=x
x=3.09855
now we have:
6.81% of 45.5=3.09855
Hope this helps!
The statement is always true because right angles measure 90 degrees and if you add them you get 180 and supplementary angles are angles that add up to 180.
Hope this helps :)
Answer:
53°
Step-by-step explanation:
It is given that the total measurement of the two angles combined would equate to 116°.
It is also given that m∠WXY is 10° more then m∠ZXY.
Set the system of equation:
m∠1 + m∠2 = 116°
m∠1 = m∠2 + 10°
First, plug in "m∠2 + 10" for m∠1 in the first equation:
m∠1 + m∠2 = 116°
(m∠2 + 10) + m∠2 = 116°
Simplify. Combine like terms:
2(m∠2) + 10 = 116
Next, isolate the <em>variable</em>, m∠2. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
First, subtract 10 from both sides of the equation:
2(m∠2) + 10 (-10) = 116 (-10)
2(m∠2) = 116 - 10
2(m∠2) = 106
Next, divide 2 from both sides of the equation:
(2(m∠2))/2 = (106)/2
m∠2 = 106/2 = 53°
53° is your answer.
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missing number is 8. there is a pattern with the input and output numbers.
Answer:
After reflection over the x-axis, we have the coordinates as follows;
A’ (5,-2)
B’ ( 1,-2)
C’ (3,-6)
Step-by-step explanation:
Here, we want to find the coordinates A’ B’ and C’ after a reflection over the x-axis
By reflecting over the x-axis, the y-coordinate is bound to change in sign
So if we have a Point (x,y) and we reflect over the x-axis, the image of the point after reflection would turn to (x,-y)
We simply go on to negate the value of the y-coordinate
Mathematically if we apply these to the given points, what we get are the following;
A’ (5,-2)
B’ ( 1,-2)
C’ (3,-6)
