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o-na [289]
4 years ago
15

What is the property of 5(11z + 6z + 29) ?

Mathematics
2 answers:
alexira [117]4 years ago
8 0


Associative allows the combining of like terms (Both with variable z)
Distributive allows the 5 to distribute through

5(11z+6z+29)
5(17z+29)
5(17z)+5(29)
<span>85z+145</span>
loris [4]4 years ago
5 0
You times everything on the inside of the bracket by the number on the outside of the bracket and then simplify? BIDMAS. 55z+30z+145 which simplifys to 85z+145  <span />
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Answer:

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Step-by-step explanation:

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Which one is equivalent
allsm [11]

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Step-by-step explanation:

sin300=-(√3)/2

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7 0
3 years ago
The average of a list of 4 numbers is 90.0. A new list of 4 numbers has the same first 3 numbers as the original list, but the f
Thepotemich [5.8K]

Answer:

the average of this new list of numbers is 94

Step-by-step explanation:

Hello!

To answer this question we will assign a letter to each number for the first list and the second list of numbers, remembering that the last number of the first list is 80 and the last number of the second list is 96

for the first list

\frac{a+b+c+80}{4} =90

for the new list

\frac{a+b+c+96}{4} =X

To solve this problem consider the following

1.X is the average value of the second list

2. We will assign a Y value to the sum of the numbers a, b, c.

a + b + c = Y to create two new equations

for the first list

\frac{y+80}{4} =90

solving  for Y

Y=(90)(4)-80=280

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for the second list

\frac{y+96}{4} =X\\

\frac{280+96}{4} =X\\x=94

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4 0
3 years ago
Read 2 more answers
The outside diameter of the igloo is 12 feet. The thickness of each block of ice that was used to construct the igloo is 1.5 fee
mojhsa [17]
The first thing we are going to do for this case is to model the igloo as a hemisphere.
 The volume of the hemisphere is:
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the amount of space of the living area inside the igloo is:
 
V = 303.1 feet ^ 3
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3 years ago
A dependent means t-test determines if the differences between scores on the pretest and posttest measures differ significantly
lara31 [8.8K]

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Benefits of pre-test measurements

This design is superior to the post-test-only control design because it adds pre-tests. Addition of pre-test: Improve your design ability to detect effects. You can investigate the impact of interventions on various sublevels of pretesting.

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Learn more about pretesting. here: brainly.com/question/968894

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