A.
because the total distance of every triangle 180. Add the two other angles so 42+ 57 =99. Then you have to subtract those two combined angles to find the missing one from the total distance, which is 180. 180-99=81. the answer is A. 81
Answer:
37 7/8
Step-by-step explanation:
First you make the equation
14 5/8 = _ - 20 - 3 1/4
They all have to make 14 5/8 so then solve
x+-93/4 = 117/8
x=303/8
Simplified:
x=37 7/8
Answer:
W=2001.24 newton meters
Caution: check units and arithmetic - I often make errors.
Step-by-step explanation:
Work is force times distance.
Denote height by h where h=0 is at ground level.
Denote the mass of the bucket and rope at height h by m(h).
The rate at which the bucket loses mass with height is (20-16)/10=0.4 kg/m
The rate at which the rope between the bucket and the top of the building loses mass is 0.4 kg/m
The initial mass of the bucket and rope is
![m_{0}=20+0.4+0.4(10)=24.4](https://tex.z-dn.net/?f=m_%7B0%7D%3D20%2B0.4%2B0.4%2810%29%3D24.4)
The mass at height h is
![m(h)=24.4-0.8h](https://tex.z-dn.net/?f=m%28h%29%3D24.4-0.8h)
The force required at height h is
m(h)g
where g is the gravitational acceleration.
g=9.81 meters/sec/sec
The work required is
![\int\limits^b_a {m(h)g} \, dh](https://tex.z-dn.net/?f=%5Cint%5Climits%5Eb_a%20%7Bm%28h%29g%7D%20%5C%2C%20dh)
Where a=0 and b=10
![g\int\limits^b_a {(24.4-0.8h)} \, dh=g(24.4h-0.4h^2)\left \{ {{10} \atop {0}} \right.](https://tex.z-dn.net/?f=g%5Cint%5Climits%5Eb_a%20%7B%2824.4-0.8h%29%7D%20%5C%2C%20dh%3Dg%2824.4h-0.4h%5E2%29%5Cleft%20%5C%7B%20%7B%7B10%7D%20%5Catop%20%7B0%7D%7D%20%5Cright.)
g(244-40)=204g
W=2001.24 newton meters
You will fail life and never succeeded because you only got 35 points
Density = mass / volume
Object A:
3g/cm^3 = 12g/V
V = 4cm^3
Object B:
5g/cm^3 = 12g/V
V = 12/5cm^3 or 2.4cm^3
Object A has a greater volume by 1.6cm^3