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Sedaia [141]
3 years ago
12

Multiply -3i and it’s conjugate. Simplify.

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
5 0

Answer:

-3 + 9i

Step-by-step explanation:

The conjugate of -3i is - 3 - i.

(- 3 i) × (- 3 - i)

Multiply both terms.

-3 + 9i

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SOVA2 [1]

Answer:

1.8 × 10^10

Step-by-step explanation:

(7.2 × 10 = 72)

(72) ÷ (4 × 10^-9) = 1.8 × 10^10

3 0
2 years ago
The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 -57, where t is the time
cupoosta [38]

A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:

1\leq t\geq \sqrt{2}

Step-by-step explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation

h =20-5t^{2}-----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height h = 15m  

Put height value in equation 1

15 =20-5t^{2}

5t^{2} =20-15

5t^{2} =5

t^{2} =1

t =\pm1

We know that the time is always positive, therefore t=1

when the stuntman is 10m above the ground.

height h = 10m  

Put height value in equation 1

10 =20-5t^{2}

5t^{2} =20-10

5t^{2} =10

t^{2} =\frac{10}{5}

t^{2} =2

t=\pm\sqrt{2}

t=\sqrt{2}

Therefore ,time interval of camera film him is 1\leq t\geq \sqrt{2}

7 0
3 years ago
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43. ALGEBRA Assume that your current
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Answer:

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Step-by-step explanation:

7 0
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An algebraic expression, where "a number" is the letter x. You do not need to simplify.
Lemur [1.5K]

Answer:

x^3-7

Step-by-step explanation:

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3 years ago
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