The first step to solving an equation like this is to find the slope of a line that will be perpendicular to the line given. The slope of a line that's perpendicular to another line is the negative reciprocal. The negative reciprocal of -1/5 is 5. So, so far our equation is y = 5x + b. Now, to find what b is equal to, we should substitute the values of x and y from the point (1,2) since we know that our line goes through the point. Our equation becomes:
2 = 5 + b
b= -3
That means that the equation of our new line is y = 5x - 3
Step-by-step explanation:
Your problem → 5y+5/2 / 25y-20/40y^2-32y
5y+5/2÷25y-20/40y^2-32y
=5⋅y+5/2÷25×y-20/40×y^2-32×y
=5y+5/2÷25×y-20/40×y^2-32y
=5y+5/2×1/25×y-20/40×y^2-32y
=5y+y/10-20/40×y^2-32y
=5y+y/10-y^2/2-32y
=5y×10+y-y^2×5-32y×10 ÷ 10
=50y+y-5y2-320y ÷ 10
= -269y-5y^2 / 10
The answer is b I’m pretty sure
We have the formula S= r * theta , where S is arc length , r is radius , and theta is central angle in radians
So AB= 4 * 45* π/180 = π units
To get 1 you need to multiply -3/8 by -2/2/3 or -2.67
