All categories

1 year ago

Solve the system of equations. I need the answer today x=2-y x-2y-11=0

Mathematics

1 answer:

mel-nik [20]1 year ago

3 0

Answer:

(5, -3)

Step-by-step explanation:

if x=2-y then 2-y-2y-11=0

-3y-9=0

-3y=9

y= -3

x= 2+3=5

You might be interested in

sergey [27]

Answer:80

Step-by-step explanation:

3 0

2 years ago

Find the surface area of the triangular prism?

viva [34]

Answer:

Step-by-step explanation:

Surface area of a triangular prism

Height = 8cm

12cm

10cm

This given as:

S.A = B + Ph

8 0

2 years ago

At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is

Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = $\frac{dx}{dt}$

ship B is sailing north at 20 km/h = $\frac{dy}{dt}$

here x and y are the sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find $\frac{dz}{dt}$ at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

$z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we | | get \\$

$z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h$

derivative first equation w . r. to t we get

$2z\frac{dz}{dt} =$ $-2(130-x)\frac{dx}{dt}$ $+2y\frac{dy}{dt}$

$\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]$

$\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }$

$= \frac{1100}{85.44}\\ = 12.87km/h$

8 0

3 years ago

Can someone help me with this problem pls

GREYUIT [131]

Answer:

my answer was 7.5

Step-by-step explanation:

2b+3b-10

4b+3b-10

10-7b=3b fraction bar means divide so...

__ 2

4b because... b-2b=4b and 8-4b=4b

3/4 =7.5 because 4 cant go into three so you add a decimal and a zero and move decimal up and 4 can go into 30 7 time which equals 28 and 30-28 is 2 add another zero and its 20 and 4 goes in 5 times which equals 20 and 20-20=0 so its 7.5 (i hope this helps ;)

8 0

3 years ago

Genius question: A long level railway bridge passes over a railroad track, which is 100 feet below it and at right angles to it.

nataly862011 [7]

Answer: <u>110 feet per second</u>

Step-by-step explanation:

In this problem we will assume that the car at 45 miles per hour is moving into the x direction with a high of 100 feet, and the train is going in the y direction, so they trajectories will made an angle of 90º.

Now we can calculate the speed of the trains in feet per second so:

$S1=\frac{45*5280}{3600}=66$

$S2=\frac{60*5280}{3600}=88$

So we can make a right triangle with sides 66 and 88 and the hypotenuse will be the rate that the trains will separate per second so:

$h=\sqrt{66^{2} +88^{2} } =\sqrt{4356+7744}$

$h=\sqrt{12100}=110$

Is important to have in mind that the initial high is not going to change how fast the trains will separate, however, if we are going to calculate the distance we should have it in the calculations.

7 0

2 years ago