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2 years ago

7

Simplify the rational expression: 5y+5/2 ÷ 25y-20/40y²-32y

1 answer:

NNADVOKAT [17]2 years ago

4 0

Step-by-step explanation:

Your problem → 5y+5/2 / 25y-20/40y^2-32y

5y+5/2÷25y-20/40y^2-32y

=5⋅y+5/2÷25×y-20/40×y^2-32×y

=5y+5/2÷25×y-20/40×y^2-32y

=5y+5/2×1/25×y-20/40×y^2-32y

=5y+y/10-20/40×y^2-32y

=5y+y/10-y^2/2-32y

=5y×10+y-y^2×5-32y×10 ÷ 10

=50y+y-5y2-320y ÷ 10

= -269y-5y^2 / 10

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3 years ago

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3 years ago

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2 years ago

Which ordered pairs are solutions to the inequality

Kipish [7]

Answer:

(1,-1)

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(5,-3)

Step-by-step explanation:

we know that

If a ordered pair is a solution of the inequality, then the ordered pair must satisfy the inequality

we have

$y-2x \leq -3$

Verify each case

case 1) we have

(1,-1)

substitute the value of x and the value of y in the inequality and then compare the results

$-1-2(1) \leq -3$

$-3 \leq -3$ ----> is true

therefore

The ordered pair is a solution of the inequality

case 2) we have

(7,12)

substitute the value of x and the value of y in the inequality and then compare the results

$12-2(7) \leq -3$

$-12 \leq -3$ ----> is true

therefore

The ordered pair is a solution of the inequality

case 3) we have

(-6,-3)

substitute the value of x and the value of y in the inequality and then compare the results

$-3-2(-6) \leq -3$

$9 \leq -3$ ----> is not true

therefore

The ordered pair is not a solution of the inequality

case 4) we have

(0,-2)

substitute the value of x and the value of y in the inequality and then compare the results

$-2-2(0) \leq -3$

$-2 \leq -3$ ----> is not true

therefore

The ordered pair is not a solution of the inequality

case 5) we have

(5,-3)

substitute the value of x and the value of y in the inequality and then compare the results

$-3-2(5) \leq -3$

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therefore

The ordered pair is a solution of the inequality

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3 years ago