<img src="https://tex.z-dn.net/?f=g%28x%29%20%3D%20%28x%20-%201%29%20%7B%7D%5E%7B2%7D%20%20-%203" id="TexFormula1" title="g(x) =

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Anon25 [30]

3 years ago

(x - 1) {}^{2} - 3" alt="g(x) = (x - 1) {}^{2} - 3" align="absmiddle" class="latex-formula">
Find...
$g {}^{2} (1)$

Mathematics

1 answer:

I am Lyosha [343]3 years ago

3 0

Answer:

Step-by-step explanation

g(x) = (x - 1)^2 - 3

g(1) = (1-1)^2 - 3 = -3

so g^2 (1) = (-3) ^2

= 9.

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consider the following scenario: Assume daily protein intake values in a population of athletes are known to have a standard dev

Kipish [7]

Answer:

The 95% confidence interval for the population mean daily protein intake is between 69.97g and 84.03g.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.96*\frac{58.6}{\sqrt{267}} = 7.03$

The lower end of the interval is the sample mean subtracted by M. So it is 77 - 7.03 = 69.97g.

The upper end of the interval is the sample mean added to M. So it is 77 + 7.03 = 84.03g.

The 95% confidence interval for the population mean daily protein intake is between 69.97g and 84.03g.

5 0

4 years ago

PLEASE HELP, i will give BRAINLIEST to the best answer.

sveticcg [70]

Answer: x 50 y 5

Step-by-step explanation: In the graph

4 0

3 years ago

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Eggs ares sold in boxes. A small box holds 6 eggs hina buys x small boxes of eggs write down in terms of x the total number of e

krok68 [10]

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5 0

3 years ago

44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access

DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.

FileSystemLocked → ∀x Access(x, SystemMailbox)

(c)

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0

3 years ago

Anyone have a answer for this?

LiRa [457]

Answer:

36.1 meters

Step-by-step explanation:

Since this is a rectangle, the parallel sides are equal to each other, meaning we technically already know all the side lengths.

I'll choose to look at the bottom triangle in this case

30 is already there, and the other leg should be 20. Knowing this, we can plug these into the pythagorean theorem.

20 is A, 30 is B, and the missing side is C

$a^{2} + b^{2} = c^{2}\\20^{2} + 30^{2} = c^{2} \\400 + 900 = 1300 \\\sqrt{1300} = 36.06\\$

C, the missing side to the nearest tenth is 36.1 meters

7 0

3 years ago