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Anon25 [30]
4 years ago
13

(x - 1) {}^{2} - 3" alt="g(x) = (x - 1) {}^{2} - 3" align="absmiddle" class="latex-formula">
Find...
g {}^{2} (1)
​
Mathematics
1 answer:
I am Lyosha [343]4 years ago
3 0

Answer:

9.

Step-by-step explanation

g(x) = (x - 1)^2 - 3

g(1) = (1-1)^2 - 3 = -3

so g^2 (1) = (-3) ^2

= 9.

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(The quadratic formula is highly unnecessary in this problem, however. You could easily divide all values by 2 to get w²-14w+49=0, which factors into (w-7)²=0, for which 7 is the only solution which puts a factor of the quadratic equal to 0.)


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