<img src="https://tex.z-dn.net/?f=g%28x%29%20%3D%20%28x%20-%201%29%20%7B%7D%5E%7B2%7D%20%20-%203" id="TexFormula1" title="g(x) =

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Anon25 [30]

4 years ago

(x - 1) {}^{2} - 3" alt="g(x) = (x - 1) {}^{2} - 3" align="absmiddle" class="latex-formula">
Find...
$g {}^{2} (1)$

Mathematics

1 answer:

I am Lyosha [343]4 years ago

3 0

Answer:

Step-by-step explanation

g(x) = (x - 1)^2 - 3

g(1) = (1-1)^2 - 3 = -3

so g^2 (1) = (-3) ^2

= 9.

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What is the solution to the system of equations?<br> y = 2/3 x + 3<br> X= -2

ludmilkaskok [199]

The solution to the given system of equations is x = -2, y = 5/3. That is (-2, 5/3)

<h3>Solving system of equations </h3>

From the question, we are to determine the solution to the given system of equations

The given system of equation is

y = 2/3 x + 3 ----------- (1)

x= -2 ----------- (2)

The value of x has been given in the second equation of the system of equations.

Now, we will determine the value of y

From the second equation, we have that

x = -2

Substitute the value of x into the first equation,

y = 2/3 x + 3

y = 2/3 (-2) + 3

y = -4/3 + 3

y = 5/3

Hence, the solution to the given system of equations is x = -2, y = 5/3. That is (-2, 5/3)

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1) write a system on equations with the solution (2, -3). Work the problem out using the substitution method

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The system of the equations that have the solution of (2, -3) are given below.

3x + 2y = 0 and 3y = 2x - 13

<h3>What is the linear system?</h3>

A Linear system is a system in which the degree of the variable in the equation is one. It may contain one, two, or more than two variables.

Write a system of equations with the solution (2, -3).

From a single point, an infinite number of lines pass through this point.

Let one line is passing through the origin. Then the equation of the line will be

$\rm y = \dfrac{-3}{2} (x)\\\\y = -1.5x$

And the other line is perpendicular to the line which is passing through the origin and a point (2, -3).

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Then this line also passes through a point (2, -3). Then the value of c will be

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Then the equation of the line will be

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