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3 years ago

Simplify the expression.

Mathematics

2 answers:

Anna35 [415]3 years ago

4 0

6,372 I used a calculator, I hope this helps

Shtirlitz [24]3 years ago

3 0

(10.8-3) × (93-3) ÷ 0.1

= 7.8 × 90 ÷ 0.1 = 7.8 × 9 = 70.2

hope it helped :-)

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which polynomial correctly combines the like terms and expresses the given polynomial in standard form? 8mn5-2m6+5m2n4-m3n3+n6-4

Lelechka [254]

Answer:

The answer would be 7mn^5 - 2m^6 + 14m^2n^4 - 5m^3n^3 + n^6

Step-by-step explanation:

In order to find that answer, start by grouping all of the terms by their variable values. Ones that are the same should be combined.

8mn^5 - mn^5 = 7mn^5

2m^6 - 4m^6 = -2m^6

5m^2n^4 + 9m^2n^4 = 14m^2n^4

-m^3n^3 - 4m^3n^3 = -5m^3n^3

n^6 = n^6

Now we simply combine them all to get

7mn^5 - 2m^6 + 14m^2n^4 - 5m^3n^3 + n^6

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3 years ago

Write 63/16 as a improper fraction

Kamila [148]

3 15/16. ( I hope you know how to write it)

6 0

2 years ago

Read 2 more answers

PLEASE PLEASE PLEASE HELP ME

lubasha [3.4K]

Answer:

CE = 17

Step-by-step explanation:

∵ m∠D = 90

∵ DK ⊥ CE

∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK

In the two Δ KDE and KCD:

∵ m∠KDE = m∠KCD

∵ m∠DKE = m∠CKD

∵ DK is a common side

∴ Δ KDE is similar to ΔKCD

∴ $\frac{KD}{KC}=\frac{DE}{CD}=\frac{KE}{KD}$

∵ DE : CD = 5 : 3

∴ $\frac{KD}{KC}=\frac{5}{3}$

∴ KD = 5/3 KC

∵ KE = KC + 8

∵ $\frac{KE}{KD}=\frac{5}{3}$

∴ $\frac{KC+8}{\frac{5}{3}KC }=\frac{5}{3}$

∴ $KC + 8 = \frac{25}{9}KC$

∴ $\frac{25}{9}KC - KC=8$

∴ $\frac{16}{9}KC=8$

∴ KC = (8 × 9) ÷ 16 = 4.5

∴ KE = 8 + 4.5 = 12.5

∴ CE = 12.5 + 4.5 = 17

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2 years ago

Will mark as BRAINLIEST!!!

Nadusha1986 [10]

Answer:

talk on here

Step-by-step explanation:

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2 years ago

A cone has a base with a radius of 9 mm and a height of 13 mm. What is the volume of the cone?

avanturin [10]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - a cone with base radius 9mm and height 13 mm

To calculate - volume of the cone

We know that ,

$Volume \: of \: cone = \frac{1}{3}\pi \: r {}^{2} h \\$

substituting the values in the formula ,

$Volume = \frac{1}{3} \times 3.14 \times 9 \times 9 \times 13 \\ \\ \implies \: 1.05 \times 81 \times 13 \\ \\ \implies \: 1105.65 \: mm {}^{3}$

hope helpful ~

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1 year ago