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BARSIC [14]
3 years ago
5

Is C=15P a direct or partial variation

Mathematics
2 answers:
Neporo4naja [7]3 years ago
5 0
I think a partial variation
Scilla [17]3 years ago
3 0
I think it’s partial variation
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Eight years from now,Oana will be twice as old as her brother is now. Oana is now 12 years old.How old is her brother now?
makkiz [27]
Her brother is 10 years old
4 0
3 years ago
Read 2 more answers
Can someone please help with this or explain how to do it. I'm not very sure where to begin ToT
larisa86 [58]

Answer:

d. 12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(6y^40z^4 + 5x^55)

Step-by-step explanation:

First, we find the greatest common factor of 12x^23y^40z^9 and 10x^78z^5.

We work on the numbers, then on x, then on y, then on z.

We start with the GCF of 12 and 10.

10 = 2 * 5

12 = 2 * 3 * 3

The only factor 10 and 12 have in common is 2, so the GCF of 12 and 10 is 2.

Now we work on x. We have x^23 and x^78.

x^23 has 23 factors of x.

x^78 has 78 factors of x.

Since x^23 and x^78 have both at least 23 factors of x, x^23 is the GCF of x.

Now we work on y.

There is y^40 in one term, but there is no y in the other term. There is no GCF for the y.

Now we work on z. The first term has z^9. the second term has z^5. They both have at least 5 factors of z, so the GCF of z is z^5.

Now we put all the parts of the GCF together, and the GCF of the two terms is

2x^23z^5

We use option d. to factor.

12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(___a____ + ____b___)

We already have the GCF outside the parentheses. Now we need to figure out what goes inside the parentheses.

The terms that go in positions a and b are the terms that when multiplied by the GCF give you the original expression.

We now work on position a.

What do you multiply by 2x^23z^5 to get 12x^23y^40z^9?

Answer: 6y^40z^4

Now we have

12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(6y^40z^4 + ____b___)

Now we do the same for position b.

What do you multiply by 2x^23z^5 to get 10x^78z^5?

Answer: 5x^55

Now we have

12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(6y^40z^4 + 5x^55)

Answer: d. 12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(6y^40z^4 + 5x^55)

5 0
2 years ago
Pleaseeee helppp it’s been due since a week ago
MAVERICK [17]
I think 20 Did you try googling it?
3 0
2 years ago
Read 2 more answers
1.Which statement about two negative numbers is true? .
Ugo [173]

Answer:

To negative numbers makes a positive number.

(only in dividing and multiplying)

Step-by-step explanation:

Please mark me brainliest

3 0
3 years ago
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4.021&gt;<br> A. 4.201<br> B. 4.12<br> C. 4.012<br> D. 4.211<br> E. None
Scilla [17]

(C.) 4.012


4.021 is greater than 4.012

7 0
3 years ago
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