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Alja [10]
2 years ago
13

Solve –4x = –36. –9 –32 9 –40

Mathematics
2 answers:
MArishka [77]2 years ago
8 0
Hi there!

Great question! :D

Since there is a variable right next to the -4, we know it means to multiply. But, we will do the opposite operation - Division!

Here's how it works:

Divide both sides by -4. Why both? Because what you do to one side, you have to treat the other equally (or the other will feel slighted!).

\frac{-4x}{4} =  \frac{-36}{4}

x = 9

Now, we can see simply that x = 9

Here's a question some people ask when solving for x -

* Why is that the answer? How do you know?

Because you can always substitute the x for the 9. Earlier we mentioned that a variable next to a number means to multiply.

So, -4 * 9 = -36 WE WERE RIGHT!!!

Another question:

*Negative 36? Why would the answer not be -9?

We can eliminate 2 answers already - The negative ones. Negative + negative = positive, and our 36 here is negative, and the 9 is positive, and so a formula you want to keep in mind is:

negative + positive = negative.
positive + positive = negative.
negative + negative = positive.

Hope this helps! :D
butalik [34]2 years ago
5 0
First you start out with your equation:
-4x = -36

Using reverse operations, divide both sides by -4. Since you're dividing a negative by a negative, you get a positive answer.

x = 9
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<h3><u>Answer:</u></h3>

\boxed{\boxed{\pink{\sf \leadsto Hence \ the \ area \ of \ shaded \ region \ is 264 cm^2}}}

<h3><u>Step-by-step explanation:</u></h3>

Here , two circles are given which are concentric. The radius of larger circle is 10cm and that of smaller circle is 4cm . And we need to find thelarea of shaded region.

From the figure it's clear that the area of shaded region will be the difference of areas of two circles.

Let the,

  • Radius of smaller circle be r .
  • Radius of smaller circle be r .
  • Area of shaded region be \bf Area_{shaded}

\bf \implies Area_{Shaded}= Area_{bigger}-Area_{smaller} \\\\\bf\implies Area_{Shaded} = \pi R^2 - \pi r^2  \\\\\bf\implies Area_{shaded} = \pi ( R^2-r^2)  \\\\\bf\implies Area_{shaded} = \pi [ (10cm)^2 - (4cm)^2]  \\\\\bf\implies Area_{shaded}  = \pi [ 100cm^2-16cm^2]  \\\\\bf\implies Area_{shaded}  = \pi \times 84cm^2  \\\\\bf\implies Area_{shaded}  = \dfrac{22}{7}\times 84cm^2  \\\\\bf\implies \boxed{\red{\bf Area_{shaded} = 264 cm^2 }}

<h3><u>Hence </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> the</u><u> </u><u>shaded </u><u>region</u><u> is</u><u> </u><u>2</u><u>6</u><u>4</u><u> </u><u>cm²</u><u>.</u></h3>

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2 years ago
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