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Lerok [7]
2 years ago
7

What is the value of x?

Mathematics
1 answer:
Anit [1.1K]2 years ago
7 0

Answer:

Step-by-step explanation:

Set this up according to the Triangle Proportionality Theorem:

\frac{3x}{4x}=\frac{3x+7}{5x-8}

Cross multiply to get

3x(5x-8)=4x(3x+7)

and simplify to get

15x^2-24x=12x^2+28x

Get everything on one side of the equals sign and solve for x:

3x^2-52x=0 and

x(3x-52)=0

By the Zero Product Property,

x = 0 or 3x - 52 = 0 so x = 17 1/3

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She lost 17 pounds don’t know question
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3 years ago
What number must be added to the expression below to complete the square? x^2+x. a.1/4 b.1/2 c.2 d.1
torisob [31]

Option a. 1/4 is the right answer

Step-by-step explanation:

Given expression is:

x^2+x

Here

we know that

a = x

In order to find the number which should be added

comparing with the formula

(a+b)^2 = a^2+2ab+b^2

2ab = x\\2.x.b = x\\b=\frac{x}{2x}\\b = \frac{1}{2}

So, we will add the square of 1/2 which is 1/4

Hence,

Option a. 1/4 is the right answer

Keywords: Expressions, polynomials

Learn more about polynomials at:

  • brainly.com/question/629998
  • brainly.com/question/6208262

#LearnwithBrainly

3 0
3 years ago
Need to find the ratio
wolverine [178]

Answer:

B

Step-by-step explanation:

CosA = AB/AC = 12/20 = 3/5

6 0
2 years ago
I'm have some issues with the problem shown in the screenshot and would love some help.
KiRa [710]

The dimensions and volume of the largest box formed by the 18 in. by 35 in. cardboard are;

  • Width ≈ 8.89 in., length ≈ 24.89 in., height ≈ 4.55 in.

  • Maximum volume of the box is approximately 1048.6 in.³

<h3>How can the dimensions and volume of the box be calculated?</h3>

The given dimensions of the cardboard are;

Width = 18 inches

Length = 35 inches

Let <em>x </em>represent the side lengths of the cut squares, we have;

Width of the box formed = 18 - 2•x

Length of the box = 35 - 2•x

Height of the box = x

Volume, <em>V</em>, of the box is therefore;

V = (18 - 2•x) × (35 - 2•x) × x = 4•x³ - 106•x² + 630•x

By differentiation, at the extreme locations, we have;

\frac{d V }{dx}  =  \frac{d( 4 \cdot \:  {x}^{3}  - 106 \cdot \:  {x}^{2}  + 630\cdot \:  {x} )  }{dx} = 0

Which gives;

\frac{d V }{dx}  =12\cdot \:  {x}^{2}  -  212\cdot \:  {x} + 630 = 0

6•x² - 106•x + 315 = 0

x  =  \frac{ - 6 \pm \sqrt{106 ^2 - 4 \times 6 \times 315} }{2 \times 6}

Therefore;

x ≈ 4.55, or x ≈ -5.55

When x ≈ 4.55, we have;

V = 4•x³ - 106•x² + 630•x

Which gives;

V ≈ 1048.6

When x ≈ -5.55, we have;

V ≈ -7450.8

The dimensions of the box that gives the maximum volume are therefore;

  • Width ≈ 18 - 2×4.55 in. = 8.89 in.

  • Length of the box ≈ 35 - 2×4.55 in. = 24.89 in.

  • Height = x ≈ 4.55 in.

  • The maximum volume of the box, <em>V </em><em> </em>≈ 1048.6 in.³

Learn more about differentiation and integration here:

brainly.com/question/13058734

#SPJ1

7 0
1 year ago
Given that f(x)=2x+3 and g(x)=x-6, what is the composition f(g(1))?
Tresset [83]

Answer:

D/0

Step-by-step explanation:

the domain of (g o f )(x) is "all x > 0".

8 0
2 years ago
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