∠GDE is supplementary to ∠DEF and also supplementary to ∠FGD
Step-by-step explanation:
To use the supplementary property to identify a parallelogram. The condition must be that that the same-side interior angles (consecutive angles) are supplementary.
Thus for parallelogram DEFG
D --------------------E
/ /
G---------------------F
Thus, we have it that the condition that is most sufficient to show that quadrilateral DEFG is a parallelogram is
Here you go. Just remember PEMDAS.
P-parentheses
E- exponents
M-multiplication
D-division
A-addition
S-subtraction
That is the order you will do it in.
