Answer:
1/7
Step-by-step explanation:
If one child was born on a Monday, then we don't have to consider that when solving the question, as it asks if both children were born on a Monday.
Thus, we only need to find the probability that the second child is born on a Monday. Since there are 7 days in a week and equally likely that the child is born on any day, then the probability of the child being born on a Monday would be 1/7.
we know that
The probability that "at least one" is the probability of exactly one, exactly 2, exactly 3, 4 and 5 contain salmonella.
The easiest way to solve this is to recognise that "at least one" is ALL 100% of the possibilities EXCEPT that none have salmonella.
If the probability that any one egg has 1/6 chance of salmonella
then
the probability that any one egg will not have salmonella = 5/6.
Therefore
for all 5 to not have salmonella
= (5/6)^5 = 3125 / 7776
= 0.401877 = 0.40 to 2 decimal places
REMEMBER this is the probability that NONE have salmonella
Therefore
the probability that at least one does = 1 - 0.40
= 0.60
the answer is
0.60 or 60%
Answer:
Step-by-step explanation:
hello:
x²-4x=0 means : x(x-4)=0
x=0 or x-4=0
conclusion : x=0 and x= 4 ...answer : B
600 elves
25% = 1/4
1/4 of the total = 150.
1/4 x 4 = 1 (total)
150 x 4 = 600
there are 600 elves
