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elena-s [515]
4 years ago
7

What is (4x+1)-(3x+4)

Mathematics
2 answers:
ch4aika [34]4 years ago
7 0

Answer:

x+5

Step-by-step explanation:

hjlf4 years ago
4 0
I think the answer is x - 3
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4x4x4x4x4 and 4^5

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April and Sanjay are both using tools to simulate the probability that a family with three children will have exactly one girl.
azamat
<span>The simulations have different theoretical probabilities of a 3-child family having exactly one girl, and the experimental probabilities they generate may differ.</span>
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3 years ago
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g An urn contains 150 white balls and 50 black balls. Four balls are drawn at random one at a time. Determine the probability th
xxTIMURxx [149]

Answer:

With replacement, 0.2109 = 21.09% probability that there are 2 black balls and 2 white balls in the sample.

Without replacement, 0.2116 = 21.16% probability that there are 2 black balls and 2 white balls in the sample.

Step-by-step explanation:

For sampling with replacement, we use the binomial distribution. Without replacement, we use the hypergeometric distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Sampling with replacement:

I consider a success choosing a black ball, so p = \frac{50}{150+50} = \frac{50}{200} = 0.25

We want 2 black balls and 2 white, 2 + 2 = 4, so n = 4, and we want P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{4,2}.(0.25)^{2}.(0.75)^{2} = 0.2109

With replacement, 0.2109 = 21.09% probability that there are 2 black balls and 2 white balls in the sample.

Sampling without replacement:

150 + 50 = 200 total balls, so N = 200

Sample of 4, so n = 4

50 are black, so k = 50

We want P(X = 2).

P(X = 2) = h(2,200,4,50) = \frac{C_{50,2}*C_{150,2}}{C_{200,4}} = 0.2116

Without replacement, 0.2116 = 21.16% probability that there are 2 black balls and 2 white balls in the sample.

3 0
3 years ago
There are 300 men and women at an afterschool meeting. 3/5 of the people are women. How many women are at the meeting? How many
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Answer:

Well as a fraction it would be 2/5, if you would like it as a number you divide 300 by 3/5 and use the leftovers.

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A recipe for cake calls for a ratio of 1 cup of sugar for every 2 cups of flour. If Janelle wants
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3 cups of sugar and 6 cups of sugar

PLZ MARK BRAINLIEST!!!

Step-by-step explanation:

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