Question

Write an equation for the line perpendicular to 4x - 12y = 2 and passing through point (10, -1)

Answer 1

Answer:

3x+y=-31

Step-by-step explanation:

$4x - 12y = 2\\12y = 4x-2\\y=\frac{x}{3}-\frac{1}{6}$

Slope of perpendicular line is -3.

$y=-3x+b$

Sub in the point (10, -1)

$-1=-3(10)+b\\-1=30+b\\b=-31\\y=-3x-31\\3x+y=-31$