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Reptile [31]
3 years ago
8

Please please please help me with this questionwhich is the correct answer​

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
5 0

Answer:

  (a)  (a² +3a -1)(a² -3a -1)

Step-by-step explanation:

The constant term of the product of the factors will be equal to the product of their constants. Since you want that product to be +1, the signs of the factor constants must be the same. That eliminates choices (c) and (d).

__

To tell which of choices (a) and (b) is correct, we can compute the squared term in their product. Let's do it in a generic way, with the constant (±1) being represented by "c".

We want the a² term in the product ...

  (a² +3a +c)(a² -3a +c)

That term will be the result of multiplying both sets of first and last terms, and adding the product of the middle terms:

  (a²·c) +(a²·c) -9a² = a²(2c-9)

So, we want the factor (2c-9) to be -11, which means c=-1, not +1.

The correct factorization of the given expression is ...

  (a² +3a -1)(a² -3a -1) . . . . matches choice A

You might be interested in
Mrs. Lee randomly surveyed 25 of her 125 students about their pets. Her survey
raketka [301]

Answer:

My figure would have 3 overlapping regions, each representing dogs, cats, or fish.  The overlapping parts represent those areas where owners have more than one pet.

Now, we know the number owners that have dogs is 14 (place this number outside one of the 3 large regions and call it dogs.  Do the same for cats (10) and fish (5).  At this point it's important to remember that only some of the 14 dog owners have only dogs.  Same for cats and fish.

In fact, we know that 4 owners have both dogs and cats.  So, on the figure where the dog region and cat region overlap, write 4.  Do the same where the dog and fish regions overlap and write 3.

What this means is that of the 14 dog owners, 7 of them own more than a dog.  So, 7 dog owners own only dogs:

14 - 7 = 7

Use the same approach for each of the other pets:

Cats: 10 owners have cats; 4 have dogs and cats and 1 has a cat and a fish.  So, 5 owners have only cats (10 - 5).

Fish: 5 owners have fish; 3 have dogs and fish and 1 has a cat and a fish.  So 1 owner has only fish (5 - 4).

Then, in summary:

Owners that have:

Only Dogs - 7

Only Cats - 5

Only Fish - 1

Dogs AND Cats - 4

Dogs AND Fish - 3

Cats AND Fish - 1

The total number of owners that have at least one pet then is:

7 + 5 + 1 + 4 + 3 + 1 = 21

So, since there are 26 total owners, 5 must not own a dog, cat, or fish.

hope it helps!!!!!!!!!!!!!!!!!!!

I put lot's of work into it

4 0
3 years ago
Can someone help me please this is due tomorrow
solmaris [256]

Answer:

Step-by-step explanation:

5 0
3 years ago
Use the drawing tool(s) to form the correct answer on the provided graph.
NikAS [45]

Answer:

Here's one way to do it

Step-by-step explanation:

1. Solve the inequality for y

5x - y > -3

-y > -5x - 3

y < 5x + 3

2. Plot a few points for the "y =" line

I chose

\begin{gathered}\begin{array}{rr}\mathbf{x} & \mathbf{y} \\-2 & -7 \\-1 & -2 \\0 & 3 \\1 & 8 \\2 & 13 \\\end{array}\end{gathered}

x

−2

−1

0

1

2

y

−7

−2

3

8

13

You should get a graph like Fig 1.

3. Draw a straight line through the points

Make it a dashed line because the inequality is "<", to show that points on the line do not satisfy the inequality.

See Fig. 2.

4. Test a point to see if it satisfies the inequality

I like to use the origin,(0,0), for easy calculating.

y < 5x + 3

0 < 0 + 3

0 < 3. TRUE.

The condition is TRUE.

Shade the side of the line that contains the point (the bottom side).

And you're done (See Fig. 3).

6 0
3 years ago
Jenna uses 18 inches of ribbon for each box she wraps. How many yards of ribbon does she needs to wrap 4 boxes?
eduard

Answer:

Jenna needs 2 yards of ribbon to wrap 4 boxes.

Step-by-step explanation:

First, we can find how many inches of ribbon she needs.

18*4=72

She needs 72 inches of ribbon for 4 yards.

There are 36 inches in a yard.

72/36=2

Jenna needs 2 yards of ribbon to wrap 4 boxes.

6 0
3 years ago
Read 2 more answers
A jar contains 30 red, 30 blue, and 60
kiruha [24]

The probability of picking red button is \frac{1}{4}

<u>Solution:</u>

Given, A jar contains 30 red, 30 blue, and 60 white buttons.  

You pick one button at a random choice,  

We have to find the probability that it is red button.

Now, total number of buttons = 30 + 30 + 60 = 120 buttons.

Number of favourable cases for red button = 30 red buttons.

The probability of an event is given as:

\text { probability of a event }=\frac{\text { favourable ways to pick red }}{\text { total possiblities }}

=\frac{30}{120}=\frac{1}{4}

Thus the probability that it is red is \frac{1}{4}

3 0
3 years ago
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