the answer would be in order 30, 45, 45. Hope this helped could I possibly get brainliest?
Answer:
Step-by-step explanation:
12/C-8d²
The numerator, which is 12 do not need any simplifying. some we center more on the denominator, c-8d².
C-8d² = 1 /C^8 × d²
=D²/C^8
Therefore,
12÷D²/C^8= 12 × C^8/D²
=12C^8/D²
Answer:
+7 and -3
Step-by-step explanation:
+7 and -3
Answer:
x = 11
Step-by-step explanation:
Take the fifth root on both sides.
27(x-2) = 3^5
27x-54 = 3^5
27x = 243 + 54
27x = 297
x = 297/27
x = 11
Answer:
The period of Y increases by a factor of with respect to the period of X
Step-by-step explanation:
The equation shows the relationship between the orbital period of a planet, T, and the average distance from the planet to the sun, A, in astronomical units, AU. If planet Y is k times the average distance from the sun as planet X, at what factor does the orbital period increase?
For the planet Y:
For planet X:
To know the factor of aumeto we compared with
We know that the distance "a" from planet Y is k times larger than the distance from planet X to the sun. So:
So
Then, the period of Y increases by a factor of with respect to the period of X