Simplify the following:
(k^3 k^7)/3 - 5
Combine powers. (k^3 k^7)/3 = k^(7 + 3)/3:
k^(7 + 3)/3 - 5
7 + 3 = 10:
k^10/3 - 5
Put each term in k^10/3 - 5 over the common denominator 3: k^10/3 - 5 = k^10/3 - 15/3:
k^10/3 - 15/3
k^10/3 - 15/3 = (k^10 - 15)/3:
Answer: (k^10 - 15)/3
I don't seem to comprehend what you are asking?
Answer:
Change in sulfur oxide in the air = 
Step-by-step explanation:
Data provided in the question:
Relation between the amount of sulfur oxide in the air and the population as:
S² = 110P² + 20P + 600
Population growth rate, 
= 10 people per month
Now,
change in sulfur oxide with time i.e 
differentiating the given relation with respect to time 't'
we have
= 
+ 20
at P = 100 and = 10 people per month
we have
= 2 × 110 × 100 × 10 + 20
or
= 220020
or
= 
or
Change in sulfur oxide in the air =
Answer:
approx 7.81 Exactly: √61
Step-by-step explanation:
Use Pythag theorem: 5^2 + 6^2 = hyp^2 (line AS)
25 + 36 = 61
hyp = √61 or about 7.81
<span>y - 2418.6 = 5.9(x - 54)
y - 2418.6 = 5.9x - 318.6
y = 5.9x + 2100
f(x) = 5.9x + 2100 (this is our function)
.
Now we can answer:
What is the weight of the plane with 26 gallons of fuel in its tank?
f(26) = 5.9(26) + 2100 = 2253.4 pounds
(Put me as brainiest!!!! <3)</span>
