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mariarad [96]
3 years ago
15

In a survey of more than 6000 people, 95% of the respondents claimed to prefer Penelope's Puffy Popcorn over any other brand of

popcorn. The respondents being which of the following groups of people would most likely call into question the results of the survey? A. People who were promised free samples of Penelope's Puffy Popcorn for completing the survey B. People whose names were randomly chosen from a telephone book C. People who were randomly stopped and asked their opinions while walking down the street D. People who blindly tested 10 brands of popcorn and were asked to choose their favorite
Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
5 0

Answer:

A. People who were promised free samples of Penelope's Puffy Popcorn for completing the survey.

Step-by-step explanation:

We are given that,

Out of 6000 people, 95% preferred Puffy Popcorn over any other brand.

It is required to find the group of people who were most likely surveyed.

Now, as we see that,

Number of people who prefer Puffy Popcorn = 95% of 6000 = 5700

Number of people who do not prefer Puffy Popcorn = 6000 - 5700 = 300

So, we get that,

Majority of the people out of the group prefers the Puffy Popcorn.

That is, the result is most likely to be a biased result.

According to the options, the group most likely to be surveyed is,

A. People who were promised free samples of Penelope's Puffy Popcorn for completing the survey.

sukhopar [10]3 years ago
4 0
<span>A. People who were promised free samples of Penelope's Puffy Popcorn for completing the survey</span>
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Y=-x+3 y = -2.x +7 = 5.​
lyudmila [28]

Answer:

Slope: 3/5

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Step-by-step explanation:

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3 years ago
Ramiro buys 50 packs of candy bars for $40 before a tax of 7.5%. He sells each candy var for 175% of what he paid before tax. ho
Zepler [3.9K]

Answer:

Cost price of each candy = $0.80, Selling price of each candy = $1.40

Step-by-step explanation:

Given:

Ramiro buys 50 packs of candy bars for $40 before a tax of 7.5%.

He sells each candy var for 175% of what he paid before tax.

Question asked:

How much does he buy each candy bar for ?

How much does he sell one for ?

Solution:

<u>By unitary method:</u>

Cost of 50 packs of candy bars = $40

Cost price of 1 pack of candy bars = \frac{40}{50} =\$0.8

Cost price of each candy = $0.80

Thus, he buy each candy bar for $0.80

Now:-

As he sells each candy var for 175% of what he paid before tax:-

Selling price of each candy = 0.80 \times 175%

                                              = 0.80\times\frac{175}{100} =\frac{140}{100}=\$1.4

Thus, he sell one candy for $1.40

3 0
3 years ago
Question 5 and 6 please help me
sp2606 [1]

Problem 5

The function is continuous for the given domain x \ge 6

This is because y = (-5/6)x+5 is itself continuous, and any interval subset of this function is also continuous. We can plug in any real number that is equal to 6 or larger, and get some y output. If we plugged in x = 6, then we'd get

y = (-5/6)x+5

y = (-5/6)*6 + 5

y = -5+5

y = 0

This is the largest y value possible. Why? Because y = (-5/6)x+5 has a negative slope, so the graph is going downhill as you read it from left to right. As x gets bigger, y gets smaller. The smallest x value allowed in the domain produces the largest y value in the range. There is no smallest y value as the y values keep going down forever.

The range is therefore y \le 0

In interval notation, you can write the range as (-\infty, 0]. The square bracket indicates "include this endpoint as part of the range".

======================================================

Problem 6

The function is discrete for this given domain. The domain itself is a discrete list of values. We cannot plug in values between say 0 and 2. We can only substitute one of those values from the list given. Consequently, the y values will also be a list, and not an interval like problem 5 had.

-----------

If you plugged in x = -4, then you should get...

y = (-1/2)*(-4)+2

y = 2+2

y = 4

So the input x = -4 lead the output y = 4

Repeat for x = -2

y = (-1/2)x+2

y = (-1/2)*(-2)+2

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and the same for x = 0 as well

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y = (-1/2)*0 + 2

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---------------

If we plugged each of these x values {-4, -2, 0, 2, 4} one at a time into the equation y = (-1/2)x+2, then we get this list of values {4, 3, 2, 1, 0}

Sorting the values from smallest to largest, we have this range {0, 1, 2, 3, 4}

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Irina18 [472]
A. x = 9 and x = 11 is the answer you are looking for

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