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VikaD [51]
2 years ago
14

249798.828806 rounded to the nearest ten

Mathematics
1 answer:
NNADVOKAT [17]2 years ago
5 0

Answer: 249800

Step-by-step explanation:

Uhh you round it.

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Solve for x:<br><br> 11x = 6x + 20
notka56 [123]

Answer:

x = 4

Step-by-step explanation:

11x= 6x +20

-6x   -6x

(subtract 6x from both sides)

5x = 20

/5x   /5x

divide 5x from both sides

x=4

3 0
3 years ago
Read 2 more answers
Line segment AB has endpoints A(1, 4) and B(2, 8) . A dilation, centered at the origin, is applied to AB¯¯¯¯¯ . The image has en
kumpel [21]
To determine the scale factor of the dilation, we determine the distances between the endpoints of the two lines through the equation,
                            d = √(x₂ - x₁)² + (y₂ - y₁)²
 Substituting the known values.

Line Segment 1:     d = √(1 - 2)² + (4 - 8)²  = 4.123

Line Segment 2:     d = √(18 - 14)² + (12 - 1)² = 11.70

Dividing the answers will give us 0.352
7 0
3 years ago
Read 2 more answers
Thomas needs to buy a cardboard sheet that will allow him to make his 224 in 3 box. To help construct the box, he decided to cut
Slav-nsk [51]

Answer:

Part 1; The volume of the box Thomas wants to make is 224 = 2·w² + 12·w

Part 2; The zeros for the equation of the function, are w = -14, or w = 8

Part 3

The width of the box is 8 inch

The length of the box, is 14 inches

The height of the box, is given as 2 inches

Part 4

Please find attached the graph of the function

Step-by-step explanation:

Part 1

The volume of the box Thomas wants to make, V = 224 in.³

The dimensions he cuts out from the length and width = 2 in² each

The length of the box = 6 inches + The width of the box

Let <em>l</em> represent the length of the box and let <em>w</em> represent the width of the box, we have;

l = 6 + w

The height of the box, h = The length of the cut out square = 2 inches

The volume of the box, V = Length, l × Width, w × Height, h

∴ V = l × w × h

l = 6 + w, h = 2

∴ V = (6 + w) × w × 2

V = 2·w² + 12·w,

The equation of the volume of the box, V = 2·w² + 12·w, where, V = 224

∴ 224 = 2·w² + 12·w

Part 2

The zeros of the equation for the volume of the box, V = 2·w² + 12·w, where, V = 224 are found as follows;

V = 224 = 2·w² + 12·w

∴ 2·w² + 12·w - 224 = 0

Dividing by 2 gives;

(2·w² + 12·w - 224)/2 = w² + 6·w - 112 = 0

∴ (w + 14) × (w - 8) = 0

The zeros for the equation of the function, are w = -14, or w = 8

Part 3

We reject the value, w = -14, therefore, the width of the box, w = 8 inch

The length of the box, l = 6 + w

∴ l = 6 + 8 = 14

The length of the box, l = 8 inches

The height of the box, <em>h</em>, is given as h = 2 inches

Part 4

The graph of the function created with MS Excel is attached

4 0
3 years ago
Here try to figure out this problem
Marysya12 [62]

Answer:

2

Step-by-step explanation:

2 is the slope, it's going up 2, and right 1 which is 2/1 or just 2

Hope this helps

7 0
3 years ago
What type of correlation does the data set display?
lara31 [8.8K]

Answer:

B-NO CORRELATION.....

4 0
3 years ago
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