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VikaD [51]
2 years ago
14

249798.828806 rounded to the nearest ten

Mathematics
1 answer:
NNADVOKAT [17]2 years ago
5 0

Answer: 249800

Step-by-step explanation:

Uhh you round it.

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I need help with both of these please I will be giving a brainlyist to the fist person to answer​
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Mary measured the heights of two different plants every day. Plant A was 1 inch tall when
seropon [69]

The heights of plant A and plant B will be equal on the day 8.

<h3>How to find the heights of the trees?</h3>

The height of the tree can be found as follows:

The equation for plant A can be described as follows:

y = 1 + 0.5x

where

x = number of days

y = height

The equation for plant B can be described as follows:

y = 3 + 0.25x

Therefore, for the height to be equal

1 + 0.5x =  3 + 0.25x

1 - 3 = 0.25x  - 0.5x

-2 = -0.25x

x = 2 / 0.25

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7 0
1 year ago
A researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playi
Andreas93 [3]

Answer:

Proportion of the students recalled more than 15 names is 91.77%.

Step-by-step explanation:

We are given that a researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playing the name game, the students were asked to recall as many first names of fellow students as possible.

The mean number of names recalled was 19.41 with a standard deviation of 3.17.

<em>Let X = number of names recalled</em>

SO, X ~ N(\mu = 19.41,\sigma^{2} = 3.17^{2})

The z-score probability distribution is given by ;

                  Z = \frac{X-\mu}{\sigma} } } ~ N(0,1)

where, \mu = mean number of names recalled = 19.41

            \sigma = standard deviation = 3.17

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, proportion of the students recalled more than 15 names is given by = P(X > 15 names)

     P(X > 15) = P( \frac{X-\mu}{{\sigma} } } > \frac{15-19.41}{3.17}  } ) = P(Z > -1.39)

                                                      = P(Z < 1.39) = 0.9177  {using z table}

<em>Therefore, proportion of the students recalled more than 15 names is </em><em>91.77%.</em>

4 0
3 years ago
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