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3 years ago

PLEASE HELP ASAP!!!!!!!!!!1

Mathematics

1 answer:

IRISSAK [1]3 years ago

6 0

Hello from MrBillDoesMath!

Answer: Commutative Property

Discussion: The commutative property, generally, indicates that

a + b = b + a for any number. In other words one can "flip around" the values being added and no change the result..

Step 4: 5y + 10 + 6y

Step 5: 5y + 6y + 10

IN this problem the commutative property is applied to the boldfaced values shown above.

Regards, MrB

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PLEASE HELP ME! Drag the expressions into the boxes to correctly complete the table.

Kamila [148]

The polynomials are:

$x^4+3x^3-5x^2-7x+20$

$x^3-2x^2+x-12$

$x^2+3x^5-6x+12x^3$

Not a polynomial are:

$4\sqrt[3]{x} -\sqrt{x} -20$

$\frac{5}{x^3}-\frac{1}{x^2}+\frac{8}{x}-40$

$x^{-3}-x^{-2}-6x^{-1}+8$

Solution:

Polynomial is an expression with variables and coefficients,

Which involves only the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables

Option 1

$4\sqrt[3]{x} -\sqrt{x} -20$

Polynomial does not include roots

This is not a polynomial equation

Option 2

$x^4+3x^3-5x^2-7x+20$

This is polynomial expression involving addition and subtraction between terms with non-negative integer exponents of variables

Option 3

$\frac{5}{x^3}-\frac{1}{x^2}+\frac{8}{x}-40$

This is not a polynomial. This equations involves negative integer exponents of variables

Option 4

$x^3-2x^2+x-12$

This is a polynomial involving addition and subtraction between terms with non-negative integer exponents of variables

Option 5

$x^{-3}-x^{-2}-6x^{-1}+8$

This is not a polynomial. This equations involves negative integer exponents of variables

Option 6

$x^2+3x^5-6x+12x^3$

This is a polynomial involving addition and subtraction between terms with non-negative integer exponents of variables

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3 years ago

Write an equation of a line that passes through (5,

enyata [817]

Answer:

y = 1/5x - 11

Step-by-step explanation:

perpendicular to a line means we flip the slope to opposite of what it is

in other wrds, since your slope is -5, your new slope for the line perpendicular to it would be 1/5.

Now we just use the same equation to find the y-intercept, which is b.

y = mx + b; m is your slope and b is your y intercept.

use the points given; (5, -10).

-10 = 1/5(5) + b

-10 = 1 + b

-11 = b

now put your equation together since you have all the pieces

y = 1/5x - 11

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3 years ago