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lord [1]
3 years ago
5

PLEASE HELP ME! Drag the expressions into the boxes to correctly complete the table.

Mathematics
1 answer:
Kamila [148]3 years ago
5 0

<em><u>The polynomials are:</u></em>

x^4+3x^3-5x^2-7x+20

x^3-2x^2+x-12

x^2+3x^5-6x+12x^3

<em><u>Not a polynomial are:</u></em>

4\sqrt[3]{x} -\sqrt{x}  -20

\frac{5}{x^3}-\frac{1}{x^2}+\frac{8}{x}-40

x^{-3}-x^{-2}-6x^{-1}+8

<em><u>Solution:</u></em>

Polynomial is an expression with variables and coefficients,

Which involves only the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables

<em><u>Option 1</u></em>

4\sqrt[3]{x} -\sqrt{x}  -20

Polynomial does not include roots

This is not a polynomial equation

<em><u>Option 2</u></em>

x^4+3x^3-5x^2-7x+20

This is polynomial expression involving addition and subtraction between terms with non-negative integer exponents of variables

<em><u>Option 3</u></em>

\frac{5}{x^3}-\frac{1}{x^2}+\frac{8}{x}-40

This is not a polynomial. This equations involves negative integer exponents of variables

<em><u>Option 4</u></em>

x^3-2x^2+x-12

This is a polynomial involving addition and subtraction between terms with non-negative integer exponents of variables

<em><u>Option 5</u></em>

x^{-3}-x^{-2}-6x^{-1}+8

This is not a polynomial. This equations involves negative integer exponents of variables

<em><u>Option 6</u></em>

x^2+3x^5-6x+12x^3

This is a polynomial involving addition and subtraction between terms with non-negative integer exponents of variables

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1. CYNARG

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In which C is the index of the Ciphered letter in the alphabet, P is the index of the original letter and o is the offset.

Finding the offset:

O is coded B

O is the 15th letter in the alphabet, so P = 15.

B is the 2nd letter in the alphabet, so C = 2

C = (P + o) \text{mod} 26

2 = (15 + o) \text{mod} 26

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So

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PLANET:

P

P is the 16th letter in the alphabet.

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So P is coded C.

L

L is the 12th letter in the alphabet:

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A

A is the 1st letter in the alphabet

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A is coded N

N

N is the 14th letter in the alphabet

C = (14 + 13) \text{mod} 26 = 1

N is coded A

E

E is the 5th letter in the alphabet

C = (5 + 13) \text{mod} 26 = 18

E is coded R

So the correct answer is:

1. CYNARG

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