Question

Can someone plz help me!!! 5-7?!

Answer 1

Answer:

#5: d=22, #6: $m=4\frac1{10}$, #7: $2\frac3{11}=z$

Step-by-step explanation:

#5:

$2\cdot (4\cdot5-3^2)=2\cdot (4\cdot5-3\cdot3)=2\cdot (20-9)=2\cdot11=22$

#6:

$5\frac25-1\frac3{10}=5\frac4{10}-1\frac3{10}=4\frac1{10}$

#7:

$\frac{40-15}{5+6}=\frac{25}{11}=2\frac3{11}$

Answer 2

Answer:

5. $d = 22$

6. $m = 4\frac{1}{10}$

7. $z = 2\frac{3}{11}$

Step-by-step explanation:

5. $d = 2 (4$ · $5 - 3^2)$

Solving the terms inside the brackets first:

$d = 2 (20 - 9)$

$d = 2 (11)$

$d = 22$

6. $m = 5\frac{2}{5} - 1\frac{3}{10}$

$m = \frac{27}{5} - \frac{13}{10}$

By taking LCM:

$m = \frac{54 - 13}{10}$

$m = \frac{41}{10}$

$m = 4\frac{1}{10}$

7. $\frac{40-15}{5+6} = z$

Taking the denominator to the other side of the equation and multiplying it there:

$40 - 15 = z (5 + 6)$

$25 = 5z + 6z$

$11z = 25$

$z = \frac{25}{11}$

$z = 2\frac{3}{11}$