Using the triangle similarity postulates, you can verify that
Answer: VT equals 62
Step-by-step explanation: In the square with sides STUV, the point W is a midpoint on the diagonal of the square such that the diagonal line SU is divided into two equal halves by the lines SW and WU. Also note that a square has two diagonals whose measurements are equal, that is, line SU equals line VT.
If the point W is the midpoint of SU, then we can conclude that SW equals WU. This means;
2x + 13 = 8x - 41
Collect like terms and you now have,
13 + 41 = 8x - 2x
54 = 6x
Divide both sides of the equation by 6
9 = x
Having calculated the value of x, remember that SW plus WU equals SU. And diagonal SU equals diagonal VT.
Therefore, VT is calculated as follows;
VT = SW + WU
VT = 2x + 13 + 8x - 41
VT = 2(9) + 13 + 8(9) - 41
VT = 18 + 13 + 72 - 41
VT = 62
Given:
Diameter of the hole = 30 cm
To find:
The area of the hole.
Solution:
The radius of a circle is always half of the diameter. It is given that the diameter of the hole is 30 cm. So, the radius of the hole is:
Area of a circle is:
Putting 
and in the above formula, we get
Therefore, the area of the hold is 706.5 square cm.
The ball was initially thrown from a height of 5.5 feet and 5.5 is y intercept that it throm from 5.5 feet.
10x^2-170x is the answer I think you're looking for
