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3 years ago

What is z? A.88 B.92 C.95 D.124

Mathematics

1 answer:

Free_Kalibri [48]3 years ago

7 0

Answer:

imma just say c cuz u didnt put nothing up there to show z

Step-by-step explanation:

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The coordinates of the vertices of a polygon are (-2, 1). (-3, 3), (-1, 5), (2, 4), and (2, 1). What is the perimeter of the pol

kobusy [5.1K]

Answer:

$15.2\ units$

Step-by-step explanation:

step 1

Plot the vertices of the polygon to better understand the problem

we have

$A(-2, 1). B(-3, 3), C(-1, 5), D(2, 4),E(2, 1)$

using a graphing tool

The polygon is a pentagon (the number of sides is 5)

see the attached figure

The perimeter is equal to

$P=AB+BC+CD+DE+AE$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 2

Find the distance AB

$A(-2, 1). B(-3, 3)$

substitute in the formula

$d=\sqrt{(3-1)^{2}+(-3+2)^{2}}$

$d=\sqrt{(2)^{2}+(-1)^{2}}$

$d_A_B=\sqrt{5}=2.24\ units$

step 3

Find the distance BC

$B(-3, 3), C(-1, 5)$

substitute in the formula

$d=\sqrt{(5-3)^{2}+(-1+3)^{2}}$

$d=\sqrt{(2)^{2}+(2)^{2}}$

$d_B_C=\sqrt{8}=2.83\ units$

step 4

Find the distance CD

$C(-1, 5), D(2, 4)$

substitute in the formula

$d=\sqrt{(4-5)^{2}+(2+1)^{2}}$

$d=\sqrt{(-1)^{2}+(3)^{2}}$

$d_C_D=\sqrt{10}=3.16\ units$

step 5

Find the distance DE

$D(2, 4),E(2, 1)$

substitute in the formula

$d=\sqrt{(1-4)^{2}+(2-2)^{2}}$

$d=\sqrt{(-3)^{2}+(0)^{2}}$

$d_D_E=\sqrt{9}\ units$

$d_D_E=3\ units$

step 6

Find the distance AE

$A(-2, 1).E(2, 1)$

substitute in the formula

$d=\sqrt{(1-1)^{2}+(2+2)^{2}}$

$d=\sqrt{(0)^{2}+(4)^{2}}$

$d_A_E=\sqrt{16}\ units$

$d_A_E=4\ units$

step 7

Find the perimeter

$P=AB+BC+CD+DE+AE$

substitute the values

$P=2.24+2.83+3.16+3+4=15.23\ units$

Round to the nearest tenth of a unit

$P=15.2\ units$

6 0

3 years ago

What is the awnser to the circled equations?

pshichka [43]

Answer:

$y = - \frac{1}{3}x - 1$

Step-by-step explanation:

We have to write an equation of a line which passes through the given point (-9,2) and is perpendicular to the given straight line y = 3x - 12 ........... (1)

Now, equation (1) is in the slope-intercept form and the slope of the line is 3.

Let, m is the slope of the required line.

So, 3m = -1

{Since, the product of the slopes of two perpendicular straight lines is -1}

⇒ $m = - \frac{1}{3}$

Therefore, the equation of the required line in slope intercept form is

$y = - \frac{1}{3} x + c$ {Where c is a constant}

Now, this above equation passes through the point (-9,2) point.

So, $2 = - \frac{1}{3} \times (-9) + c$

⇒ 2 = 3 + c

⇒ c = - 1

Therefore, the equation of the required straight line is $y = - \frac{1}{3}x - 1$ (Answer)

5 0

4 years ago

Reflect the shape A in the line x=1 What are the coordinates of the vertices of the image?

mestny [16]

Answer:

(0,4) (0,7) (-2,4)

Step-by-step explanation:

The line x=1 is a vertical line that passes through the point (1,0). So we then place the new triangle at equal distance from the line.

I hope this helps!

please mark brainliest!!

6 0

2 years ago

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What shape is this cross-section?

hoa [83]

Answer:

Circle

Step-by-step explanation:

5 0

2 years ago

100 POINTS!!!!!!

Andrews [41]

Answer:

A 4x2=7-15 X=

Step-by-step explanation:

B como dedos de los dedos de losdos para el desayuno

C te como para el chico del

4 0

3 years ago