What is the slope of a line that passes through (-3,5) and (4,3)?

1 answer:

5 0

to find a slope you subtract the y value of the 2nd point from the y value of the 1st point then you devide that by the difference of the x value of the 2nd point subtracted from the x value of the 1st point. so 5-3 devided by -3-4, 5-3=2, -3-4=-7. so m = 2/-7 is your slope. the slope is usually represented with the letter m.

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babunello [35]

To find the slope, you use the slope formula (m):

$m=\frac{y_2-y_1}{x_2-x_1}$ and plug in the two points

(-3, 4) = (x₁, y₁)

(2, -1) = (x₂, y₂)

$m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{-1-4}{2-(-3)}$ [two negatives cancel each other out and become positive]

$m=\frac{-1-4}{2+3}$

$m=\frac{-5}{5}$

m = -1 The slope is -1

4 0

3 years ago

Read 2 more answers

In rectangle ABCD, the angle bisector of ∠A intersects side DC at point M and the angle bisector of ∠C intersects side AB at poi

Verizon [17]

Perimeter of quadrilateral ANCM = AN+NC+CM+MA

CM=AM = x in
Therefore, AN=NC = x in
In other words, all sides of the new quadrilateral are equal.

Perimeter (P) = 4x in

Now, Cos 45 = (x-6)/x =>0.7041 = (x-6)/x => 0.7041x=x-6 =>x= 6/(1-0.70741)
x= 20.5 in

Therefore, P=4*20.5 = 82 in