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Varvara68 [4.7K]
3 years ago
13

Plz help asap I will give brainliest​

Mathematics
2 answers:
Neko [114]3 years ago
8 0

Answer:

D

Step-by-step explanation:

i had this assignment just don't feel like explaining lol

elena-s [515]3 years ago
4 0

Answer:

B

Step-by-step explanation:

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Use mathematical induction to prove that for each integer n > 4,5" > 2^2n+1 + 100.
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Answer:

The inequality that you have is 5^{n}>2^{2n+1}+100,\,n>4. You can use mathematical induction as follows:

Step-by-step explanation:

For n=5 we have:

5^{5}=3125

2^{(2(5)+1)}+100=2148

Hence, we have that 5^{5}>2^{(2(5)+1)}+100.

Now suppose that the inequality holds for n=k and let's proof that the same holds for n=k+1. In fact,

5^{k+1}=5^{k}\cdot 5>(2^{2k+1}+100)\cdot 5.

Where the last inequality holds by the induction hypothesis.Then,

5^{k+1}>(2^{2k+1}+100)\cdot (4+1)

5^{k+1}>2^{2k+1}\cdot 4+100\cdot 4+2^{2k+1}+100

5^{k+1}>2^{2k+3}+100\cdot 4

5^{k+1}>2^{2(k+1)+1}+100

Then, the inequality is True whenever n>4.

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The RANGE of the function f is
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Answer:

Step-by-step explanation:

The range of the function is what values of y from lowest to highest that are covered by the function.  The domain are the values on the left: A-E; the range are the values on the right: 1-3.  We state both domain and range in interval notation, stating only the lowest and highest values in either a set of brackets if the values are included, a set of parenthesis if the values are not included, or a mixture of both.  Our range is inclusive, so we mention the lowest and the highest only: [1, 3].

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