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3 years ago

II

Mathematics

2 answers:

nekit [7.7K]3 years ago

4 0

8 pencils would be the left over caust

mash [69]3 years ago

3 0

Answer:

Step-by-step explanation:

Because you left one pence then it is 9-1=8

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Identify terms and factors: - 4x + 2x2 y

DedPeter [7]

Answer:

=2x2y−4x

Step-by-step explanation:

4 0

3 years ago

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A pyramid has a square base with sides 100 feet long. The original height was 75 feet.

viva [34]

Step-by-step explanation:

Step 1: Find the volume of the original pyramid

$V = a^2*\frac{h}{3}$

$V=(100)^2*\frac{75}{3}$

$V=10000*25$

$V=250000$

Step 2: Find the volume of the cut off

$V=(20)^2*\frac{15}{3}$

$V = 400*5$

$V=2000$

Step 3: Find the percent that still remains

$250000-2000$

$248000$

$248000 / 250000$

$0.992*100$

$99.2$

Answer: 99.2%

8 0

3 years ago

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When You are Doing mean, median, and mode can you have a zero for the median?

san4es73 [151]

Sure, but one or more of the numbers would have to be negative.
In that case, even the mean could be zero.

Look at these numbers.
What's the mean ?

1, 2, 6, 4, 7, -20

8 0

3 years ago

a circle is inscribed in a square. the circumference of the circle is increading at a constant rate of 6 inches per second. As t

Burka [1]

Answer:

The rate at which Perimeter of the square is increasing is $\frac{24}{\pi} \ in/secs$ .

Step-by-step explanation:

Given:

Circumference of the circle = $2\pi r$

Rate of change of in circumference = 6 in/secs

We need to find the rate at which the perimeter of the square is increasing

Solution:

Now we know that;

$\frac{d(2\pi r)}{dt} =6\\\\2\pi\frac{dr}{dt}=6\\\\\frac{dr}{dt}=\frac{6}{2\pi}\\\\\frac{dr}{dt}=\frac{3}{\pi}$

Now we know that;

side of the square= diameter of the circle

side of the square = $2r$

Now Perimeter of the square is given by 4 times length of the side.

$P=4\times 2r =8r$

Now we need to find the rate at which Perimeter is increasing so we will find the derivative of perimeter.

$\frac{dP}{dt}= \frac{d(8r)}{dt}\\\\\frac{dP}{dt}= 8\times\frac{dr}{dt}$

But $\frac{dr}{dt} =\frac{3}{\pi}$

So we get;

$\frac{dP}{dt}= 8\times\frac{3}{\pi}\\\\\frac{dP}{dt}= \frac{24}{\pi}\ in/sec$

Hence The rate at which Perimeter of the square is increasing is $\frac{24}{\pi} \ in/secs$ .

5 0

3 years ago

Select the correct answer.

DiKsa [7]

when doing substitution,you must make one a subject,which is y in this case.To make y the subject,you must move -2y to 4x to make the y positive,that leaves us with 2y+4x=5.Now move the 4x to 5 to make 2y=5-4x.Lastly,to make y the subject,divide both side by 2 to remove the 2 from the y, which leaves us with y=5-4x/2

5 0

2 years ago