A square patio has an area of 122 square feet. How long is each side of the patio to the nearest 0.05?

Mathematics

1 answer:

jasenka [17]2 years ago

3 0

Should be About 25 feet as your answer

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Complete the square to solve the equation below.

sasho [114]

Hello there!

x² + x = 7/4
x² + - 7/4 = 0

Now we gonna use the quadratic formula to find x
a= 1
b=1
c = -1.75

x = -b+/-√b² -4ac all of them divide by 2a
x = -(1)+/-√(1)² - (4)(1)(-1.75) all of them divide by 2(1)
x= -1+/-√8 all of them divide by 2
x = -1/2 + √2 or x = -1/2 - √2

The correct option is option C

I hope that helps!

4 0

3 years ago

Spiral Review Hayden is attending a craft show. The cost of an admission ticket is $8. The cost of a raffle ticket for a handmad

LekaFEV [45]

Answer:

Step-by-step explanation:

$45- $8 = 37 (aka his raffle ticket spending money)

37÷5= 7, so the max # of raffle tickets he can buy is 7.

7 0

3 years ago

Help me pls, im stuck!!!! :))

timofeeve [1]

Answer:

y=8x

Step-by-step explanation:

The graph starts at the origin so there won't be a y intercept and the slope its 8 because every book costs 8 dollars. Therefore, the equation will be y=8x. Hope this helped

7 0

3 years ago

Read 2 more answers

The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78

____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

$m-t_{a/2,n-1}\frac{s}{\sqrt{n} }$ ≤ μ ≤ $m+t_{a/2,n-1}\frac{s}{\sqrt{n} }$

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and $t_{a/2,n-1}$ is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and $t_{0.05,9}$ by 1.8331, we get that the 90% confidence interval for the mean speed is: