Answer:
Step-by-step explanation:
Total number of students = 68
Let history = H
Maths = M
English = E
n(H) = 25
n(M) = 25
n(E) = 34
n(HnMnE) = 3
Total = n(H) + n(M) + n(E) - people in exactly two groups + 2(people in exactly 3 groups) + people in none of the groups
68 = 25 + 25 + 34 - people in exactly two groups - 6 +0
68 = 84 -6 - people in exactly two groups
68 = 78 - people in exactly two groups
People in exactly two groups = 78 - 68
= 10
OR
From the venn diagram, people in exactly two groups are represented by x, y and z
Total = 25 - x - y - 3 + 25 - x - z - 3 + 34 - y - z - 3 + x + y + z + 3
68 = 50 - x - 3 + 34 - y - z - 3
68 = 84 - 6 - x - y - z
68 = 78 - x - y - z
68 - 78 = - x - y - z
-10 = -(x + y + z)
x+y+z = -10/-1
x+y+z = 10
The number of students that registered for exactly two courses = 10
Solutions
1 km = 0.621371 miles
42 km = 26.0976 miles
Answer:
9Kg, 18Kg and 63 Kg
Step-by-step explanation:
Sum the parts of the ratio, 1 + 2 + 7 = 10 parts
Divide the weight of sand by 10 to find the value of one part of the ratio
90 Kg ÷ 10 = 9 Kg ← value of 1 part of the ratio, thus
2 parts = 2 × 9 Kg = 18 Kg
7 parts = 7 × 9 Kg = 63 Kg
Thus the weights of each bag are 9 Kg, 18 Kg and 63 Kg
Answer:
H0: σ1=σ2
Ha : σ1 >σ2
B. Upper H 0H0:
sigma Subscript 1 Superscript 2σ21equals=sigma Subscript 2 Superscript 2σ22
Upper H 1H1:
sigma Subscript 1 Superscript 2σ21greater than>sigma Subscript 2 Superscript 2σ22
Step-by-step explanation:
The claim is that the treatment group has errors that <em><u>vary significantly</u></em> more than the errors of the placebo group.
The claim is the alternative hypothesis and the opposite of claim is the null hypothesis.
Vary significantly means that it is greater than so we choose the alternate hypothesis of greater than and the null hypothesis will be equal to errors of the placebo group.
So the correct choice is B.
B. Upper H 0H0:
sigma Subscript 1 Superscript 2σ21equals=sigma Subscript 2 Superscript 2σ22
Upper H 1H1:
sigma Subscript 1 Superscript 2σ21greater than>sigma Subscript 2 Superscript 2σ22
Choice A,C and D all are incorrect.
This can be written as
H0: σ1=σ2
Ha : σ1 >σ2
