P(x)=2x^3-11x^2+ax-40 if x+4 is a factor of this polynomial what is the value of a
1 answer:
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Write the function as
f(x) = x² + 6x - 4
Note that
x² + 6x = (x + 3)² - 9
Therefore
f(x) = (x 3)² - 9 - 4
= (x + 3)² - 13
The vertex is at (-3, -13)., and the curve opens upward.
The axis of symmetry is x = -3.
Answer:
The vertex of the function is (-3, 13).
The graph increases over the interval (-3, -∞)
f(x) = x² + 6x - 4
Note that
x² + 6x = (x + 3)² - 9
Therefore
f(x) = (x 3)² - 9 - 4
= (x + 3)² - 13
The vertex is at (-3, -13)., and the curve opens upward.
The axis of symmetry is x = -3.
Answer:
The vertex of the function is (-3, 13).
The graph increases over the interval (-3, -∞)
Answer:
Step-by-step explanation:
The area of a sector in terms of radians as opposed to degrees is
Filling in the formula accordingly gives us
The radians cancel out, the pi's cancel out, the 2 in the denominator cancels out (divides into 2-squared once), leaving us with
A = 1.75(2) so
A = 3.5 units squared