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kicyunya [14]
3 years ago
6

Determine the total number of roots of each polynomial function using the factored form. f (x) = (x + 5)3(x - 9)(x + 1)

Mathematics
2 answers:
zalisa [80]3 years ago
6 0

Answer:

Number of roots is 5.

Step-by-step explanation:

Since, the roots of a function f(x) is obtained when f(x) = 0,

Given expression,

f(x) = (x+5)^3(x-9)(x+1)

For finding the roots,

f(x) = 0,

(x+5)^3(x-9)(x+1)=0

(x+5)(x+5)(x+5)(x-9)(x+1) =0

By the ZERO PRODUCT property,

x + 5 = 0 or x + 5 = 0 or x + 5 = 0 or x - 9 = 0 or x + 1 =0,

⇒ x = -5, -5, -5, 9 or -1

Hence, the number of roots = 5.

densk [106]3 years ago
5 0

Answer:

Answer is 5

Step-by-step explanation:

Okay hun so let me tell u what's up here

They give us this equation and ask for the 'roots'

(x+5)^3(x-9)(x+1)

Now lemme tell you the roots of this one

-5, 9, -1

you get this from making each of them 0

The answer to this would be "3" because there are 3 roots, buT wait theRe'S mOre

(x+5) goes 3 times

So thy must recount it

-5, -5, -5, 9, -1 <-- These are the roots

that's 5 roots in total

....also I did this on edgen, got it right with 5

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Water is pumped out of a holding tank at a rate of 6-6e^-0.13t liters/minute, where t is in minutes since the pump is started. I
astraxan [27]
Procedure:

1) Integrate the function, from t =0 to t = 60 minutues to obtain the number of liters pumped out in the entire interval, and

2) Substract the result from the initial content of the tank (1000 liters).

Hands on:

Integral of (6 - 6e^-0.13t) dt  ]from t =0 to t = 60 min =

= 6t + 6 e^-0.13t / 0.13 = 6t + 46.1538 e^-0.13t ] from t =0 to t = 60 min =

6*60 + 46.1538 e^(-0.13*60) - 0 - 46.1538 = 360 + 0.01891 - 46.1538 = 313.865 liters

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Answer: 613.135 liters



 

3 0
3 years ago
Please help, i will give brainliest to whos first
Wittaler [7]

Thanks with all of my heart!

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After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modelled by the function C(t)=8(e
Alexxx [7]

Answer:

the maximum concentration of the antibiotic during the first 12 hours is 1.185 \mu g/mL at t= 2 hours.

Step-by-step explanation:

We are given the following information:

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in \mu g/mL

C(t) = 8(e^{(-0.4t)}-e^{(-0.6t)})

Thus, we are given the time interval [0,12] for t.

  • We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
  • The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.

First, we differentiate C(t) with respect to t, to get,

\frac{d(C(t))}{dt} = 8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)})

Equating the first derivative to zero, we get,

\frac{d(C(t))}{dt} = 0\\\\8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0

Solving, we get,

8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0\\\displaystyle\frac{e^{-0.4}}{e^{-0.6}} = \frac{0.6}{0.4}\\\\e^{0.2t} = 1.5\\\\t = \frac{ln(1.5)}{0.2}\\\\t \approx 2

At t = 0

C(0) = 8(e^{(0)}-e^{(0)}) = 0

At t = 2

C(2) = 8(e^{(-0.8)}-e^{(-1.2)}) = 1.185

At t = 12

C(12) = 8(e^{(-4.8)}-e^{(-7.2)}) = 0.059

Thus, the maximum concentration of the antibiotic during the first 12 hours is 1.185 \mu g/mL at t= 2 hours.

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Mashcka [7]
9(2k+3)+2=11 (k-y) 
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8 0
3 years ago
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malfutka [58]

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Now you have to decide between B and C. The intersection point has Sharon going upwards until she is 20. She started out at 70. The graph has John starting at 70. That's not right.


So we've eliminated A,D and now C.


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