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raketka [301]
3 years ago
5

Hiiioo! Can someone please help me with this❤️❤️

Mathematics
1 answer:
kotykmax [81]3 years ago
7 0

Answer:

Hello! Your answer would be, E)

Step-by-step explanation:

Hope I helped! Ask me anything if you have questions! Brainiest plz. Hope You make a 100%! Have a nice day! -Amelia♥

Is this a multiple choice?

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The volume of fuel in a tank changes at a rate given by the equation V'\left(t\right)=\frac{4t}{\sqrt[3]{t^2+3}},\:t\ge0 V ′ ( t
Ksju [112]
V'(t)=\dfrac{4t}{\sqrt[3]{t^2+3}}

The volume of fuel in the tank after 9 hours is given by

\displaystyle\int_0^9V'(t)\,\mathrm dt=\int_0^9\dfrac{4t}{(t^2+3)^{1/3}}\,\mathrm dt

To compute the integral, substitute u=t^2+3, so that \mathrm du=2t\,\mathrm dt. Then when t=0, u=0^2+3=3; when t=9, u=9^2+3=84.

\displaystyle\int_0^9V'(t)\,\mathrm dt=2\int_{t=0}^{t=9}\frac{2t}{(t^2+3)^{1/3}}\,\mathrm dt=2\int_{u=3}^{u=84}u^{-1/3}\,\mathrm du
=2\cdot\dfrac32u^{2/3}\bigg|_{u=3}^{u=84}=3(84^{2/3}-3^{2/3})\approx51.3

So the volume of fuel after 9 hours is about 51.3 gallons.
8 0
4 years ago
Tim has 39 pairs of headphones and 13 music players. Tim wants to sell all of the headphones and music players in identical pack
Doss [256]

Answer:

13 packages

Step-by-step explanation:

We need to find the highest common factor, in order to solve this problem.

So, we have to find the highest common factor of 39 and 13.

We find the highest common factor of 39 and 13 because it says in the problem” Tim has 39 pairs of headphones and 13 music players.”

And than you just find the highest common factor, after you find the highest common factor... YOU ARE DONE SOLVING THE PROBLEM!

The highest common factor will be 13

13: 1,13

39:1,3,13,39

ANSWER:13

Hope this helps!

3 0
4 years ago
Read 2 more answers
HELP ME BEFORE I GET IN TROUBLE
hram777 [196]

Answer:

453.2

it is correct

5 0
3 years ago
It costs a dollars for an adult ticket to a reggae concert
brilliants [131]

the answer is C.

12a -18s =36

(12 adult tickets= 12a) - (18 student tickets =18s) =$36

5 0
4 years ago
A rectangular prism has a width of 16 inches and a length of 10 inches. The volume of the rectangular prism is decreasing at a r
frosja888 [35]

Answer:

-3.47 inches per minute

Step-by-step explanation:

Let the height be 'h' for any time 't'.

Given:

Length of the prism (L) = 10 in

Width of the prism (w) = 16 in

The rate of change of volume of prism is, \frac{dV}{dt}=-555\ in^3/min (The negative sign implies the volume decreases with time.)

Now, rate of change of height of prism = \frac{dh}{dt}=?

Length and width remains constant.

Now, we know that, volume of a rectangular prism is given as:

Volume = Length × width × Height

V=Lwh\\\\V=10\times 16\times h\\\\V=160h

Now, differentiating both sides with respect to time 't', we get:

\frac{dV}{dt}=\frac{d}{dt}(160h)

Plug in the given values and solve for \frac{dh}{dt}. This gives,

-555=160\times \frac{dh}{dt}\\\\\frac{dh}{dt}=\frac{-555}{160}\\\\\frac{dh}{dt}=-3.47\ in/min

The negative sign implies the height decreases with time.

Therefore, the the rate of change, in inches per minute, of the height when the height is 3 inches is -3.47 inches per minute.

5 0
3 years ago
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