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ollegr [7]
3 years ago
11

What integers fall between the square root of 12

Mathematics
1 answer:
Dafna1 [17]3 years ago
7 0
The square root of 12 is 3.4.
Your integers are 3 and 4.
I hope this helps!
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Solve for x<br><br> x^2-3x+2=0
cricket20 [7]

Answer:

x=1,2

Step-by-step explanation:

x^2-3x+2=0

(x-1)(x-2)

x-1=0

x-2=0

x=1,2

6 0
3 years ago
Can someone answer this please
erma4kov [3.2K]

Answer:

4^(-11)

Step-by-step explanation:

To divide powers, subtract the exponents.

4^(-2) / 4^9

-2-9=-11

So, the answer is 4^(-11), which is basically 4 to the eleventh power.

8 0
3 years ago
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Is 3.14 a Rational, Whole Number, Integer, or Irrational number?​
IrinaVladis [17]

Answer:

the answer is a rational number

7 0
3 years ago
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Please answer the WHOLE question and explain!
exis [7]

The total weight of candies is unknown. Let x = the total weight of candies.

"One student ate 3/20 of all candies and another 1.2 lb":

The first student ate (3/20)x plus 1.2 lb which is 0.15x + 1.2.

"The second student ate 3/5 of the candies and the remaining 0.3 lb."

The second student ate (3/5)x and 0.3 lb which is 0.6x + 0.3.

Altogether the 2 students ate 0.15x + 1.2 + 0.6x + 0.3.

That was all the amount of candies, so that sum equals x.

0.15x + 1.2 + 0.6x + 0.3 = x

Now we solve the equation for x to find what the total amount of candies was.

0.75x + 1.5 = x

-0.25x = -1.5

x = 6

The total amount of candies was 6 lb.

The first student ate 0.15x + 1.2 = 0.15(6) + 1.2 = 0.9 + 1.2 = 2.1, or 2.1 lb of candies.

The second student ate 0.6x + 0.3 = 0.6(6) + 0.3 = 3.6 + 0.3 = 3.9, or 3.9 lb of candies.

Answer: The first student ate 2.1 lb of candies, and the second student ate 3.9 lb of candies.

7 0
3 years ago
The equation of a circle is (x + 3)2 + (y + 5)2 = 8. Determine the coordinates of the center of the circle.
Illusion [34]
The equation of the circle is written as: (x - h)² + (y - k)² = r²

(h,k) are the points of the center of the circle.
r is the radius.

In case of the given equation the center is (-3,-5)

Hope this helps :)
8 0
3 years ago
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