4a+6p=5 |x4| 16 a +24p =20
8a+4p=4 |x6|48 + 24p=24
------------------------------ -
-32a=-4
a=4/32
a=⅛
Answer:
x=1
Step-by-step explanation:
4^x+3=7
subtract 3
4^x=4
x=1
Given:
Consider the line segment YZ with endpoints Y(-3,-6) and Z(7,4).
To find:
The y-coordinate of the midpoint of line segment YZ.
Solution:
Midpoint formula:
![Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)](https://tex.z-dn.net/?f=Midpoint%3D%5Cleft%28%5Cdfrac%7Bx_1%2Bx_2%7D%7B2%7D%2C%5Cdfrac%7By_1%2By_2%7D%7B2%7D%5Cright%29)
The endpoints of the line segment YZ are Y(-3,-6) and Z(7,4). So, the midpoint of YZ is:
![Midpoint=\left(\dfrac{-3+7}{2},\dfrac{-6+4}{2}\right)](https://tex.z-dn.net/?f=Midpoint%3D%5Cleft%28%5Cdfrac%7B-3%2B7%7D%7B2%7D%2C%5Cdfrac%7B-6%2B4%7D%7B2%7D%5Cright%29)
![Midpoint=\left(\dfrac{4}{2},\dfrac{-2}{2}\right)](https://tex.z-dn.net/?f=Midpoint%3D%5Cleft%28%5Cdfrac%7B4%7D%7B2%7D%2C%5Cdfrac%7B-2%7D%7B2%7D%5Cright%29)
![Midpoint=\left(2,-1\right)](https://tex.z-dn.net/?f=Midpoint%3D%5Cleft%282%2C-1%5Cright%29)
Therefore, the y-coordinate of the midpoint of line segment YZ is -1.
Answer:
t = 108
Step-by-step explanation:
t - 27 =
t + 21 ( subtract
t from both sides )
t - 27 = 21 ( add 27 to both sides )
t = 48 ( multiply both sides by 9 )
4t = 432 ( divide both sides by 4 )
t = 108