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Kryger [21]
3 years ago
11

What’s the answer please help

Mathematics
1 answer:
asambeis [7]3 years ago
4 0

Answer:

4,1 and 7,6

Step-by-step explanation:

add me as brainliest

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Plzzzzzzzzzzz answer asap
stepan [7]

Answer:

A) 80

Step-by-step explanation:

b/4-23=-3

b/4=-3+23

b/4=20

b=20*4

b=80

5 0
3 years ago
Tell whether the angles are adjacent or vertical. Then find the value of x.
lozanna [386]

Answer:

x = 25

Step-by-step explanation:

The angles are vertical since they form from two lines crossing at a point and they share a same vertex.

Vertical angles are equal so

4x - 25 = 75

4x = 100

x = 25

8 0
3 years ago
2 intersecting lines are shown. A line with points M, H, K intersects a line with points L, H, J at point H. 4 angles are create
yulyashka [42]

Answer:

m = 10

Step-by-step explanation:

According to the picture attached, we can see the angles formed.

The angle on the top (5m+100) is sided with the angle 2m+10. This means that they are supplementary angles, their sum is 180°.

So,

5m+100+2m+10 = 180

5m+2m=180-100-10

7m = 70

m = 10

5 0
3 years ago
Read 2 more answers
The limit as h approaches 0 of (e^(2+h)-e^2)/h is ?
Whitepunk [10]
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h

</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
3 0
3 years ago
I need a word problem that has a negative - positive
AleksandrR [38]

Answer:

Here it is

Step-by-step explanation:

You are 58 dollars in debt, and your friend pays you 73 dollars.  How much money do you have?  Does that work for you?

8 0
2 years ago
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