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gtnhenbr [62]
3 years ago
10

Determine if the function is continuous to its domain

Mathematics
1 answer:
Maurinko [17]3 years ago
6 0

Yes, it is continuous to its domain

<h2>Explanation:</h2><h2></h2>

In order to find the domain of the function we need to get the restrictions:

1. From natural log:

x>0

2. From quotient:

x\neq 0

Matching these two restrictions the domain is:

x\in (0,\infty)

So the function is continuous to its domain because is defined for every x-value in the interval (0, \infty))

<h2>Learn more:</h2>

Functions: brainly.com/question/12891789

#LearnWithBrainly

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maxonik [38]

Answer: x = 5, x = -5  If you need more....

x = 5^{1}

x = \sqrt{25}

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In the summer, the average temperature is -18°F at the South
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-76 < -40 < -18 < 32

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3 years ago
What is the perimeter of the triangle shown on the coordinate plane, to the nearest tenth of a unit?
Akimi4 [234]

Answer:

25.6 units

Step-by-step explanation: From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).

First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}

where

(x_1,y_1) are the coordinates of the first point

(x_2,y_2) are the coordinates of the second point

- For AB:

d=\sqrt{[1-(-5)]^{2}+(4-4)^2}

d=\sqrt{(1+5)^{2}+(0)^2}

d=\sqrt{(6)^{2}}

d=6

- For BC:

d=\sqrt{(3-1)^{2} +(-4-4)^{2}}

d=\sqrt{(2)^{2} +(-8)^{2}}

d=\sqrt{4+64}

d=\sqrt{68}

d=8.24

- For AC:

d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}

d=\sqrt{(3+5)^{2} +(-8)^{2}}

d=\sqrt{(8)^{2} +64}

d=\sqrt{64+64}

d=\sqrt{128}

d=11.31

Next, now that we have our lengths, we can add them to find the perimeter of our triangle:

p=AB+BC+AC

p=6+8.24+11.31

p=25.55

p=25.6

We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.

Read more on Brainly.com - brainly.com/question/12560433#readmore

8 0
3 years ago
14/100 in simplest form
Readme [11.4K]
0.14. hope this helps
7 0
3 years ago
Read 2 more answers
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