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Natalka [10]
3 years ago
11

9497÷16 Write your answer as a whole number and remainder.

Mathematics
2 answers:
Oduvanchick [21]3 years ago
7 0

Divide 9497 with 16

9497/16 = 593 (rounded, is your whole number)

Multiply 593 with 16.

593 x 16 = 9488

Subtract 9488 from the original number

9497 - 9488 = 9

Place 9 over the divisor.

593 9/16 is your answer

hope this helps

Vanyuwa [196]3 years ago
6 0

This is a long division problem. First, we divide 94 by 16. 16 can go into 94 FIVE times: 16 * 5 = 80. 94 - 80 = 14.

Drop down the 9 to get 149 divided by 16. 16 goes into 149 NINE times: 16 * 9 = 144. 149 - 144 = 5.

Drop the 7 to get 57 divided by 16. 16 goes into 57 THREE times: 16 * 3 = 48. 157 - 148 = 9.

So, our answer is 593 with a remainder of 9.

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Which is the vertex of x2 + 10x = -17 <br><br> (-5,-8)<br><br> (5,8)<br><br> (-5,8)<br><br> (5,-8)
ad-work [718]

Answer:

vertex = (- 5, - 8)

Step-by-step explanation:

Given a quadratic in standard form : ax² + bx + c = 0 : a ≠ 0

Then the x- coordinate of the vertex is

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Hence vertex = (- 5, - 8)

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