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HACTEHA [7]
3 years ago
5

If an object is dropped from a height of 96ft, the function h(t) = -62 + 96 gives the height of the object after t seconds. When

will the object hit the ground?
Mathematics
1 answer:
Shalnov [3]3 years ago
7 0

Answer:

Step-by-step explanation:Since we want to know how much time elapsed since the object was launched until it ht the ground. At the ground, the height is 0.

 

Therefore the equation  h(t) = 80t – 16t2 becomes 0= 80t – 16t2

 

Solving the equation for t gives  80t =16t2 or 16t=80 or t=5sec

 

The object hits the ground 5 seconds after it is launched.

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cestrela7 [59]

Answer:

The maximum height of the twig is 96.6 feet off the ground

Step-by-step explanation:

To determine the maximum height of the twig,

First, we will determine the height distance covered by the twig after Mary flicks the twig up.

From the question,

Mary flicks a twig up and off of the ledge with the initial vertical velocity of 10 feet per second, that is

the initial velocity of the twig is 10 feet/second

At maximum height, the final velocity is 0

From on the equations of motions for bodies moving upwards,

v² = u² - 2gh

Where v is the final velocity

u is the initial velocity

g is the acceleration due to gravity (Take g = 9.8m/s² = 32.17 ft/s²)

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From the question

u = 10 feet/second

and v = 0 feet/second

Putting the values into the equation

v² = u² - 2gh

0² = 10² - 2(32.17)h

0 = 100 - 64.34h

64.34h = 100

h = 100/64.34

h = 1.6 feet

This is the height distance covered by the twig after Mary flicks it up.

Now, the maximum height of the twig will be the sum of the height of the rooftop from the ground and the height distance covered by the twig.

That is,

Maximum height = 95 feet + 1.6 feet

Maximum height = 96.6 feet

Hence, the maximum height of the twig is 96.6 feet off the ground.

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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