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HACTEHA [7]
3 years ago
5

If an object is dropped from a height of 96ft, the function h(t) = -62 + 96 gives the height of the object after t seconds. When

will the object hit the ground?
Mathematics
1 answer:
Shalnov [3]3 years ago
7 0

Answer:

Step-by-step explanation:Since we want to know how much time elapsed since the object was launched until it ht the ground. At the ground, the height is 0.

 

Therefore the equation  h(t) = 80t – 16t2 becomes 0= 80t – 16t2

 

Solving the equation for t gives  80t =16t2 or 16t=80 or t=5sec

 

The object hits the ground 5 seconds after it is launched.

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If ∠WOZ and ∠WOX are supplementary angles and ∠WOX and ∠XOY are complementary angles, then what is the value of x and m∠XOY?
omeli [17]

Answer:

D.x = 6; m∠XOY = 18°

Step-by-step explanation:

Supplementary angles add to 180 and complementary angles add to 90

∠WOZ + ∠WOX = 180

108 + ∠WOX = 180

∠WOX + ∠XOY = 90

∠WOX + 3x = 90

∠WOX  = 90 -3x

Replace WOX in the first equation

108 + ∠WOX = 180

108 + 90 -3x = 180

Combine like terms

198 -3x = 180

Subtract 198 from each side

-3x = 180-198

-3x = -18

Divide by -3

-3x/-3 = -18/-3

x = 6

∠XOY  = 3x = 3*6 = 18

5 0
3 years ago
Please help me ASAP!!
choli [55]

Answer:

r = -4

Step-by-step explanation:

If M is the midpoint of DE, that would mean that the distance from M to D and M to E would be the same.

This creates the equation 1-8r=13-5r.

Now it's just simple algebra.

You add 8r to both sides, creating 1=13+3r. Then, you subtract 13 from both sides, getting 3r=-12. Dividing both sides by 3 and solving for r, you get r=-4.

Checking our answer, you see that 1-8(-4)=1-(-32)=1+32=33, and 13-5(-4)=13-(-20)=13+20=33.

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The little squares at corner-B and corner-E were drawn there
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