If an object is dropped from a height of 96ft, the function h(t) = -62 + 96 gives the height of the object after t seconds. When will the object hit the ground?
1 answer:
Answer:
Step-by-step explanation:Since we want to know how much time elapsed since the object was launched until it ht the ground. At the ground, the height is 0.
Therefore the equation h(t) = 80t – 16t2 becomes 0= 80t – 16t2
Solving the equation for t gives 80t =16t2 or 16t=80 or t=5sec
The object hits the ground 5 seconds after it is launched.
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5/3 is farthest according to me
Answered by Gauthmath must click thanks and mark brainliest
Why:
1) x+y=46000
x=46000-y
2) 4%x+9,5%y=3490;
4x + 9.5y=349000; so 4*(46000-y)+9.5y=349000;
5.5y=165000
y=30000
x=46000-30000=16000
Answer:
x < 56
Step-by-step explanation:
- x + 40 > -16
-x + 40 - 40 > -16 -40
-x > -56
-x / -1 > -56 / -1
x < 56
Answer:
ok
Step-by-step explanation:
Answer:
17
Step-by-step explanation:
32+2=34
34/2= 17
