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Anuta_ua [19.1K]
3 years ago
7

Help please 75 77 82 Show your work

Mathematics
1 answer:
Daniel [21]3 years ago
4 0

Answer:Jarvis's class average is 75

Step-by-step explanation:

The total possible average score for the math course is 100

a) If the teacher rates homework at 10%, it means that the total possible score for homework

is 10/100 × 100 = 10

If his homework average is 93, then his score would be

(93×10)/100 = 9.3

b) If the teacher rates quizzes at 30%, it means that the total possible score for quizzes

is 30/100 × 100 = 30

If his quiz average is 82, then his score would be

(82×30)/100 = 24.6

c) If the teacher rates test at 40%, it means that the total possible score for quizzes

is 40/100 × 100 = 40

If his quiz average is 72, then his score would be

(72×40)/100 = 28.8

d) If the teacher rates final exam at 20%, it means that the total possible score for quizzes

is 20/100 × 100 = 20

If his final exam is 60, then his score would be

(60×20)/100 = 12

Jarvis's class average would be

9.3 + 24.6 + 28.8 + 12 = 74.7

Approximately 75

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A halloween assorted bag of candy contains 4 Snickers, 2 packages of M&M's, & 3 Butterfingers. What is the probability o
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Answer:

2/27

Step-by-step explanation:

In the question we have:

4 snickers

2 packages of M&M's

3 Butterfingers.

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Therefore, the probability of selecting some M&M's, putting them back, and then selecting a Butterfinger =

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3 0
3 years ago
Use​ Newton's method to find an approximate solution of ln(x)=10-x. Start with x_0 =9 and find x_2 .
vova2212 [387]

Answer:

x₂ = 7.9156

Step-by-step explanation:

Given the function  ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ -  f(xₙ)/f'(xₙ)

If f(x) = ln(x)+x-10

f'(x) = 1/x + 1

f(9) = ln9+9-10

f(9) = ln9- 1

f(9) = 2.1972 - 1

f(9) = 1.1972

f'(9) = 1/9 + 1

f'(9) = 10/9

f'(9) = 1.1111

x₁ = x₀ -  f(x₀)/f'(x₀)

x₁ = 9 -  1.1972/1.1111

x₁  = 9 - 1.0775

x₁  = 7.9225

x₂ = x₁ -  f(x₁)/f'(x₁)

x₂ = 7.9225 -  f(7.9225)/f'(7.9225)

f(7.9225) = ln7.9225 + 7.9225 -10

f(7.9225) = 2.0697 + 7.9225 -10

f(7.9225) = 0.0078

f'(7.9225) = 1/7.9225 + 1

f'(7.9225) = 0.1262+1

f'(7.9225) = 1.1262

x₂ = 7.9225 - 0.0078/1.1262

x₂ = 7.9225 - 0.006926

x₂ = 7.9156

<em>Hence the approximate value of x₂ is 7.9156</em>

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