Tanα=5/12
α=arctan(5/12)°
α≈22.62° (to nearest hundredth of a degree)
Answer/Step-by-step explanation:
Let's find the measure of the angles of ∆QNP.
∆QMN is am isosceles ∆, because it has two equal sides. Therefore, its base angles would be the same. Thus:
m<MNQ = ½(180 - 48) (one of the base angles of ∆QMN)
m<MNQ = ½(132) = 66°
Next, find m<QNP
m<QNP = 180° - m<MNQ (linear pair angles)
m<QNP = 180° - 66° (Substitution)
m<QNP = 114°
Next, find m<P
m<P = 180 - (m<QNP + m<PQN) (sum of ∆)
m<P = 180 - (114 + 33)
m<P = 180 - 147
m<P = 33°
Thus, in ∆QNP, there are two equal angles, namely, <P and <PQN.
An isosceles ∆ had two equal base angles. Therefore, ∆QNP must be an isosceles ∆.
Since there are 3 lines (triangle), perimeter is simply the sum of those sides
find each side using distance (d) formula:
where two points of the line lie at (x1, y1) and (x2, y2)
let's name the points of our triangle to make it easier: A = (8, 2), B = (8, 6), C = (6, 6)
So now for P add AB + BC + AC = 4+2+4.47
P = 10.47 units squared
Answer:
Step-by-step explanation: